If we want to evaluate the integral x+40 I = dx, + 64 we use the...

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If we want to evaluate the integral x+40 I = dx, + 64 we use the trigonometric substitution x = 2 tan(0) and dx = de and therefore the integral becomes, in terms of 0, I = de The antiderivative in terms of 0 is (do not forget the absolute value) I = +C Finally, when we substitute back to the variable x, the antiderivative becomes I = +C If we want to evaluate the integral x+40 I = dx, + 64 we use the trigonometric substitution x = 2 tan(0) and dx = de and therefore the integral becomes, in terms of 0, I = de The antiderivative in terms of 0 is (do not forget the absolute value) I = +C Finally, when we substitute back to the variable x, the antiderivative becomes I = +C