If you get more than 3 wrong, you will be asked to resubmit the wrong answers and show your work. The teacher will then look at your work and give you advice on what you are doing wrong. For problems 1-3, find the equation of the graph that is the set of all points equidistant from the given point and the given line. 1. F(0, 4), y = 0 O A. y= 1/8x2 + 2 O B. y= 1/8X2 - 2 O C. x=1/8/2 + 2 O D.X= 1/8/2 - 2 O E.x= -1/8/2 + 2 OF. y=-1/8x2 - 2 2. F(1/2, 0), X = -1/2 O A. y= 1/2X2 O B. X=1/272 O C.X=-1/272 O D. y= -1/2X2 O E. y= 2x2 O F. X= -22 3. F(0, -8), y = 8 O A. y2 = 0 O B. X=1/242 O C. y= 1/32X2 O D. X= 1/322 O E. x2= 0 O F. y= -1/32X2 4. Write the equation of a parabola with a vertex at the origin and the focus at (6, 0). O A. X= 1/6/2 O B. X= 1/242 O C. x= 24y O D. X= 1/242 O E. y= 1/24X2 O F. y= 6x2 5. Write the equation of a parabola with a vertex at the origin and the focus at (0, -5).5. Write the equation of a parabola with a vertex at the origin and the focus at (0, -5). O A.y=-Y,0x? O B.y= Y502 O C.y=20x2 O D.x=-Y50y? O E.x=Y0y? O F.x=-20y? 6. A cross section of the mirror of a flashlight is a parabola. It measures 6 cm across and has a depth of 2 cm. How far from the vertex should the filament of the light bulb be placed for the flashlight to have its beam run parallel to the axis of its mirror? O A.2.667 cm O B.0.889cm O C.1.125cm O D.2.25cm O E.0.444cm O F.0.75cm 7. A cross section of a reflector of a television satellite dish is a parabola that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be placed? O A.0.3125ft O B.0.78125ft O .0.2500 ft O D.1.25ft O E.0.625ft O F.1.8125ft 8. Stein Glass, Inc., makes parabolic headlights for a variety of automobiles. If one of its headlights has a parabolic surface generated by the parabola x? = 12y, where should its light bulb be placed? (Hint: Solve the equation for y before you start finding the focus.) O A.3units O B.12units O C.4units O D. 48 units O E. 36 units O F.2units For problems 9 and 10, identify the focus and the directrix of the graph of the equation. 9. y= -1/8x2 O A. focus (0, 2); directrix: y = -2 O B. focus (0, 2); directrix: y = 2 O C. focus (0, -2); directrix: y = -8 O D. focus (0, -2); directrix: y = 2 O E. focus (0, -1/8); directrix: y = 8 O F. focus (0, -8); directrix: y = 1/8 10. X= 1/2y2 O A. focus (0, -1/2); directrix: y = 1/2 O B. focus ( -1/2, 0); directrix: x = 1/2 C. focus (0, 1/2); directrix: y = 1/2 O D. focus ( 1/2, 0); directrix: X = - 1/2 O E. focus (2, 0); directrix: y = 2 units O F. focus (0, 2); directrix: x = 2 units For problems 11-13, write the equation for the circle with the given center and radius. 11. Center (0, 0), r = 7 O A. ( x - 7) 2 + (y - 7)2 = 49 O B. x2 + y2 = 7 O C. (x - 7)2 + y2 = 49 O D. X2 + (y - 7)2 = 49 O E. x2 + y2 = 49 OF. (x + 7)2 + (y- 7)2 = 7 12. Center (-6. 10), r = 2 O A. (x - 6)2 + (y+ 10)2 =4 O B. (x + 6)2 + (y+ 10)2 = 4 O C. (x - 6)2 + (y+ 10)2 = 2 O D. (x+ 6)2 + (y- 10)2 = 4 O E. (x - 10)2 + (y + 6)2 = 4 OF. (x - 10)2 + (y + 6)2 = 213. Center (-3, 0), r = 6 O A. (x + 3)2 + (y- 3)2 = 6 O B. (x - 3)2 + y2 = 36 O C. x2 + (y - 3)2 = 36 O D. x2 + ( y + 3)2 = 6 O E. ( x + 3) 2 + y2 = 36 OF. ( x + 3)2 + (y+ 3)2 = 6 14. (x - 3)2 + (y+ 1)2 = 36 O A. Center (3, -1), r = 6 O B. Center (-3, 1), r = 6 O C. Center (3, 1), r = 36 O D. Center (1, -3), r = 6 O E. Center (-1, 3), r = 6 O F. Center (1, 3), r = 36 15. (x + 6)2 + y2 = 121 O A. Center (-6, 0), r = 121 O B. Center (6, 0), r = 11 O C. Center (0, 6), r = 121 O D. Center (0, -6), r = 121 O E. Center (0, 6), r = 11 O F. Center (-6, 0), r = 11 16. (x + 4)2 + (y - 3)2 =7 O A. Center (3, -4), r =17 O B. Center (4, 3), r =17 O C. Center (-4, -3), r = 7 O D. Center (-4, 3), r = 17 O E. Center (-3, 4), r = 7 O F. Center (3, 4), r =17For problems 17 and 18, expand the standard form of a circle equation to change it to the general form. 17. (x+5)2 + y2= 18 O A. x2 + y2 + 35x - 18 = 0 O B. x2 + y2 + 10x + 43 =0 O C.x2 + y2 + 5x +7=0 O D. x2 + y2 + 35x + 18 = 0 O E. x2 + y2 + 10x +7=0 OF. x2 + y2 + 3x +7=0 18. (x + 3)2 + (y - 5)2 = 38 O A.x2 + y2 + 6x - 10 - 4=0 OB. x2 + y2 + 6x - by - 4=0 O C. x2 + y2 + 6x+ 10y -4=0 O D. x2 + y2 + 6x - by + 4 = 0 O E. x2 + y2 + 6x- 10y + 72 =0 OF. x2 + y2 + 9x - by-72 = 0 For problems 19 and 20, complete the square to change the general form of the equation to the standard form. 19. x2 + y2 + 18x + 45 = 0 O A. (x + 9)2 + y2 = 6 O B. (x + 9)2 + y2 = 36 O C. (x + 3) 2+ y2 = 36 O D. ( x - 3) 2 + y2 = 6 O E. (x - 9)2 + y2 = 36 OF. ( x - 9) 2 + y2 = 6 20. x2 + y2 - 12x + 4y + 24 = 0 O A. (x + 3)2 + (y + 4)2 = 4 O B. (x - 6)2 + (y + 2)2 = 4 O C. (x - 6)2 + (y+ 2)2 = 56 O D. (x - 3)2+ (y + 4)2 = 16 O E. (x+ 6)2 + (y- 2)2 = 4 OF. ( x - 6)2 + (y + 2)2 = 16