import java.util.Scanner;

class HammingCode $\{$

static void print$($int ar$[])\{$

for $($int i $=1$; i $<$ ar$.$length; i$++)\{$

System.out.print$($ar$[$i$])$;

$\}$

System.out.println$()$;

$\}$

static int$[]$ calculation$($int$[]$ ar$,$ int r$)\{$

for $($int i $=0$; i $<$ r; i$++)\{$

int x $=($int$)$ Math.pow$(2,$ i$)$;

for $($int j $=1$; j $<$ ar$.$length; j$++)\{$

if $((($j $>>$ i$)$ & $1)==1)\{$

if $($x $!=$ j$)$

ar$[$x$]=$ ar$[$x$]^$ ar$[$j$]$;

$\}$

$\}$

System.out.println$("$p$"+$ x $+"="+$ ar$[$x$])$;

$\}$

return ar;

$\}$

static int$[]$ generateCode$($String str$,$ int M$,$ int r$)\{$

int$[]$ ar $=$ new int$[$r $+$ M $+1]$;

int j $=0$;

for $($int i $=1$; i $<$ ar$.$length; i$++)\{$

if $(($Math$.$ceil$($Math$.$log$($i$)/$ Math.log$(2))$

$-$ Math.floor$($Math$.$log$($i$)/$ Math.log$(2)))$

$==0)\{$

ar$[$i$]=0$;

$\}$ else $\{$

ar$[$i$]=($int$)($str$.$charAt$($j$)-\text{'}0\text{'})$;

j$++$;

$\}$

$\}$

return ar;

$\}$

public static void main$($String$[]$ args$)\{$

Scanner scanner $=$ new Scanner$($System$.$in$)$;

$//$ Input message from the user

System.out.print$("$Enter Data: $")$;

String str $=$ scanner.nextLine$()$;

int M $=$ str$.$length$()$;

int k $=1$;

$//2^$K $-1>=$ M $+$ K

while $((-1+$Math.pow$(2,$ k$))<($M $+$ k $))\{$

k$++$;

$\}$

int$[]$ ar $=$ generateCode$($str$,$ M$,$ k$)$;

System.out.println$("$Generated hamming code $")$;

ar $=$ calculation$($ar$,$ k$)$;

print$($ar$)$;

scanner.close$()$;

$\}$

$\}..$you must do this hamming code $($with random$)$ noise $($error$).$

you must calculate the percentage of correcting error $($single bit error, burst error$).$ you must do it to check and correct large data

Answer rating: 100% (QA)

To implement Hamming code with random noise error and calculate the percentage of correcting errors singlebit error burst error you can modify the exi... View the full answer