In the circuit of Fig. 10-29, va = 10/2 cos t and i, = 10/2 cos...

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In the circuit of Fig. 10-29, va = 10/2 cos t and i, = 10/2 cos 2t. (a) Find the average power delivered by each source. (b) Find the current in the resistor and the average power absorbed by it. Ans. (a) Pa = P, = 80 W, (b) ir = 2/10 cos (t- 26.5°) + 2/10 cos (2t – 63.4°), PR = 160 W 10.51 %3D ll 1 H + 0.5 F 4Ω Fig. 10-29 In the circuit of Fig. 10-29, va = 10/2 cos t and i, = 10/2 cos 2t. (a) Find the average power delivered by each source. (b) Find the current in the resistor and the average power absorbed by it. Ans. (a) Pa = P, = 80 W, (b) ir = 2/10 cos (t- 26.5°) + 2/10 cos (2t – 63.4°), PR = 160 W 10.51 %3D ll 1 H + 0.5 F 4Ω Fig. 10-29

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