#include using namespace std; int main () { int stop; int result; int a; int b;...

 

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#include <iostream> using namespace std; int main () { int stop; int result; int a; int b; cin >> stop; result = 0; for (a = 3; a < 6; ++a) { for (b= 0; b < 4; ++b) { } } if } resulta; cout << result; cout <<endl; if (result > stop) ( break; } (result stop) { break; return 0; Input 14 Output #include <iostream> using namespace std; int main () { int stop; int result; int a; int b; cin >> stop; result = 0; for (a = 3; a < 6; ++a) { for (b= 0; b < 4; ++b) { } } if } resulta; cout << result; cout <<endl; if (result > stop) ( break; } (result stop) { break; return 0; Input 14 Output

Answer rating: 100% (QA)

Solution The given C code takes an input value stop and performs nested loops to calculate the sum o... View the full answer