It is commonly assumed that Z at standard conditions (psc = 14.7 psi and T=60F) is...

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It is commonly assumed that Z at standard conditions (psc = 14.7 psi and T=60°F) is equal to 1. Show whether this is a good assumption using the fluid data in Appendix C. Plot the volume versus pressure of 1 lb-mol of this gas from atmospheric pressure to the reservoir pressure, which is equal to 4613 psi. (Use a temperature of 180°F.) Comment on the shape of this curve. Composition of gas and properties: C (0.875) C2 (0.083) C3(0.021) i-C4(0.006) п-Са(0.002) i-C5(0.003) n-C5 (0.008) n-C6(0.001) C7+(0.001) Tpc = 378°R Ppc = 671 psi Yg = 0.65 Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi = 0.945 Hi = 0.0244 cp h = 78 ft = 0.27 Sw S3 0.73 0.14 rw = 0.328 ft (7 7/8-in. well) k = 0.17 md It is commonly assumed that Z at standard conditions (psc = 14.7 psi and T=60°F) is equal to 1. Show whether this is a good assumption using the fluid data in Appendix C. Plot the volume versus pressure of 1 lb-mol of this gas from atmospheric pressure to the reservoir pressure, which is equal to 4613 psi. (Use a temperature of 180°F.) Comment on the shape of this curve. Composition of gas and properties: C (0.875) C2 (0.083) C3(0.021) i-C4(0.006) п-Са(0.002) i-C5(0.003) n-C5 (0.008) n-C6(0.001) C7+(0.001) Tpc = 378°R Ppc = 671 psi Yg = 0.65 Well and Reservoir Variables T = 180°F 640°R Pi = 4613 psi = 0.945 Hi = 0.0244 cp h = 78 ft = 0.27 Sw S3 0.73 0.14 rw = 0.328 ft (7 7/8-in. well) k = 0.17 md

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Formation volume factor is defined as the ... View the full answer