OV V. m/s 500 V + + + + + + 4. (a) In the...
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OV V. m/s 500 V + + + + + + · 4. (a) In the figure, a proton is fired with an initial speed (vo) of 90000 m/s from the midpoint of the capacitor toward the positive plate as shown. The plates are 0.3 m. apart. i.Find the location (in cm) where the proton stops and turns around (use x=0 as the location of the negative plate). 26.3 X 06.84 O15.3 O37.0 O17.5 57.2 ii. What is the potential (in V) at that location? O953 0438 O 292 O254 O114 0617 iii.What is the proton's speed (in m/s) when it reaches the 130 V location? 03.72e+05 01.53e+05 O2.65e+05 O68800 O1.76e+05 05.75e+05 iii.If an electron is fired from the positive plate with an initial velocity that is 90 times faster than the initial velocity of the proton, how far (in cm) from the OV plate will it stop? O61.3 O39.7 07.33 O18.8 O 28.2 O 16.3 (b)Consider two charges of charge -8e-09 C nailed in place on the y-axis straddling the origin (one charge 0.005 m above the origin and one charge 0.005 m below the origin). A proton is at the origin and it is launched directly to the right (along the x-axis). i.What is the escape speed (in m/s) of the proton (middle charge)? (Again, assume the two outer charges are fixed in place) 09.16e+05 04.96e+06 O7.66e+06 O2.35e+06 O3.52e+06 O2.04e+06 ii.If the proton (middle charge) is launch with half of the escape speed, how far away (in m) from its starting point will it stop and turn around? O0.00930 O0.00661 O0.0144 0.00384 O0.00172 O0.00441 (c) An electric dipole consists of 0.006 kg spheres charged to +3e-09 C at the ends of a 0.16 m long non-conducting rod of mass 0.009 kg (don't try to look up "electric dipole", it wont help you. For the sake of this problem, it is just a fancy word for what I just described). The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with a field strength V/m, then released. i. What is the dipole's angular velocity (in rad/s) at the instant it is aligned with the electric field? (HINT: Look up the moment of inertia of the rotating rod about its center and don't forget the rotational kinetic energy term (along with the other terms) when you set up your conservation of energy problem). O0.100 00.211 O0.326 O0.0870 00.150 00.0390 (d) Four 1.4e-08 C charges are held in location to form a perfect square with sides of length 0.04 m. Two of the charges from opposing corners are released simultaneously, the other two are held in place. The mass of each charge is 0.006 kg.. i.How fast (in m/s) will the two released charges be moving when they are far, far away from their original location? 00.279 00.0725 00.162 O0.606 O0.392 0.186 OV V. m/s 500 V + + + + + + · 4. (a) In the figure, a proton is fired with an initial speed (vo) of 90000 m/s from the midpoint of the capacitor toward the positive plate as shown. The plates are 0.3 m. apart. i.Find the location (in cm) where the proton stops and turns around (use x=0 as the location of the negative plate). 26.3 X 06.84 O15.3 O37.0 O17.5 57.2 ii. What is the potential (in V) at that location? O953 0438 O 292 O254 O114 0617 iii.What is the proton's speed (in m/s) when it reaches the 130 V location? 03.72e+05 01.53e+05 O2.65e+05 O68800 O1.76e+05 05.75e+05 iii.If an electron is fired from the positive plate with an initial velocity that is 90 times faster than the initial velocity of the proton, how far (in cm) from the OV plate will it stop? O61.3 O39.7 07.33 O18.8 O 28.2 O 16.3 (b)Consider two charges of charge -8e-09 C nailed in place on the y-axis straddling the origin (one charge 0.005 m above the origin and one charge 0.005 m below the origin). A proton is at the origin and it is launched directly to the right (along the x-axis). i.What is the escape speed (in m/s) of the proton (middle charge)? (Again, assume the two outer charges are fixed in place) 09.16e+05 04.96e+06 O7.66e+06 O2.35e+06 O3.52e+06 O2.04e+06 ii.If the proton (middle charge) is launch with half of the escape speed, how far away (in m) from its starting point will it stop and turn around? O0.00930 O0.00661 O0.0144 0.00384 O0.00172 O0.00441 (c) An electric dipole consists of 0.006 kg spheres charged to +3e-09 C at the ends of a 0.16 m long non-conducting rod of mass 0.009 kg (don't try to look up "electric dipole", it wont help you. For the sake of this problem, it is just a fancy word for what I just described). The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with a field strength V/m, then released. i. What is the dipole's angular velocity (in rad/s) at the instant it is aligned with the electric field? (HINT: Look up the moment of inertia of the rotating rod about its center and don't forget the rotational kinetic energy term (along with the other terms) when you set up your conservation of energy problem). O0.100 00.211 O0.326 O0.0870 00.150 00.0390 (d) Four 1.4e-08 C charges are held in location to form a perfect square with sides of length 0.04 m. Two of the charges from opposing corners are released simultaneously, the other two are held in place. The mass of each charge is 0.006 kg.. i.How fast (in m/s) will the two released charges be moving when they are far, far away from their original location? 00.279 00.0725 00.162 O0.606 O0.392 0.186
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Related Book For
Fundamentals of Corporate Finance
ISBN: 978-1259024962
6th Canadian edition
Authors: Richard Brealey, Stewart Myers, Alan Marcus, Devashis Mitra, Elizabeth Maynes, William Lim
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