L = LL_ + L2 - hL L=-ih L = heti [(2) i cot 0 ()]...
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L = LL_ + L2 - hL L=-ih L = heti [(2) i cot 0 ()] L+L_ = [(322) + i (2). + cot 0 (2) + cot 0 a 1 = - [102 (sin 0g) + (0) | sin a) Derive Equation 4.131 from Equation 4.130. (3)] Eqn. 4.112 Eqn. 4.129 Eqn. 4.130 Eqn. 4.131 Eqn. 4.132 L = LL_ + L2 - hL L=-ih L = heti [(2) i cot 0 ()] L+L_ = [(322) + i (2). + cot 0 (2) + cot 0 a 1 = - [102 (sin 0g) + (0) | sin a) Derive Equation 4.131 from Equation 4.130. (3)] Eqn. 4.112 Eqn. 4.129 Eqn. 4.130 Eqn. 4.131 Eqn. 4.132
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To derive Equation 4131 from Equation 4130 we need to perform the operation L L using the given form of L in Equation 4130 Given Equation 4130 L hbar ... View the full answer
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