Let A be the matrix of coefficients of a 5 x 7 system of linear equations,...

 

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Let A be the matrix of coefficients of a 5 x 7 system of linear equations, Az = 6. Using row operations, you find that A is row equivalent to a matrix in reduced row echelon form with one row of zeroes at the bottom. 1. 0 solutions 2. 1 solution 3. infinite solutions What is rank(4)? How many free variables does the system have? (3 pts) For the given system how many possible solutions could it have? (Circle all which apply) (3 pts) For the associated homogeneous system A2=0, how many possible solutions could it have? (Circle all which apply) 1. 0 solutions 2. 1 solution 3. infinite solutions Let A be the matrix of coefficients of a 5 x 7 system of linear equations, Az = 6. Using row operations, you find that A is row equivalent to a matrix in reduced row echelon form with one row of zeroes at the bottom. 1. 0 solutions 2. 1 solution 3. infinite solutions What is rank(4)? How many free variables does the system have? (3 pts) For the given system how many possible solutions could it have? (Circle all which apply) (3 pts) For the associated homogeneous system A2=0, how many possible solutions could it have? (Circle all which apply) 1. 0 solutions 2. 1 solution 3. infinite solutions

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It is implied that there is at least one row of zeroes in the original matrix A if the reduced row e... View the full answer