Let f(x) = 20 (?1)k x2k (2k)! k=0 . Which of the following is equivalent to t f(x) dx 0 ?

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Let f(x) O O O = ¡M: ¡M: ¡Me ¡Mc k=0 k=0 k=0 20 Σ(-1)k x2k (2k)! k=0 (−1)k x2k+1 (2k+1)! k=0 (−1)k t2k-1 (2k-1)! (−1)k t²k+1 (2k+1)! (−1)k+1 +2k+1 (2k+1)! Which of the following is equivalent to [² F(x) f(x) dx? Let f(x) O O O = ¡M: ¡M: ¡Me ¡Mc k=0 k=0 k=0 20 Σ(-1)k x2k (2k)! k=0 (−1)k x2k+1 (2k+1)! k=0 (−1)k t2k-1 (2k-1)! (−1)k t²k+1 (2k+1)! (−1)k+1 +2k+1 (2k+1)! Which of the following is equivalent to [² F(x) f(x) dx?

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Let fx 20 1 x KO 2K t 20 1K2k 2x x t ... View the full answer