Let n=102 +r, where , re N, 0r9. A number a is chosen at random from...

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Let n=102 +r, where , re N, 0r9. A number a is chosen at random from the set {1, 2, 3, ..., n} and let pn denote the probability that (a 1) is divisible by 10. 70. If r = 0, then npn equals (a) 22 (c) (22 + 1) 71. If r =9, then npn equals (a) 22 (c) (2 + 1) 72. If 1 r 8, then npn equals (a) (221) (c) (2 + 1) (b) ( + 1) (d) (b) 2( + 1) (d) (b) 22 (d) Let n=102 +r, where , re N, 0r9. A number a is chosen at random from the set {1, 2, 3, ..., n} and let pn denote the probability that (a 1) is divisible by 10. 70. If r = 0, then npn equals (a) 22 (c) (22 + 1) 71. If r =9, then npn equals (a) 22 (c) (2 + 1) 72. If 1 r 8, then npn equals (a) (221) (c) (2 + 1) (b) ( + 1) (d) (b) 2( + 1) (d) (b) 22 (d)

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