A reinforced concrete circular column is supported by a square isolated footing (reinforced concrete spread footing)....
Fantastic news! We've Found the answer you've been seeking!
Question:
Transcribed Image Text:
A reinforced concrete circular column is supported by a square isolated footing (reinforced concrete spread footing). Net allowable soil pressure: net qa = 130 kPa Column loads (unfactored): D=170 kN, L = 110 kN Column diameter = 320 mm Column steel: six No. 25 bars; fy = 420 MPa, Esteel=200000 Mpa Column concrete: f=26MPa Footing concrete: f = 20MPa Required: 1- determine the dimension and the thickness of footing TABLE 3.1 Values of I, and I2 (N =H/B' and M = L/B) N M=1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 0.2 1, 0.009 0.008 0.008 0.008 0.008 0.008 0.007 0.007 0.007 0.007 0.007 12 0.041 0.042 0.042 0.042 0.042 0.042 0.043 0.043 0.043 0.043 0.043 0.4 90 0.6 0.8 1.0 1.5 2.0 3.0 4.0 5.0 6.0 7.0 00 8.0 9.0 10.0 20.0 500.0 0.033 0.032 0.031 0.030 0.029 0.028 0.028 0.027 0.027 0.027 0.027 0.066 0.068 0.069 0.070 0.070 0.071 0.071 0.072 0.072 0.073 0.073 0.066 0.064 0.063 0.061 0.060 0.059 0.058 0.057 0.056 0.056 0.055 0.079 0.081 0.083 0.085 0.087 0.088 0.089 0.090 0.091 0.091 0.092 0.104 0.102 0.100 0.098 0.096 0.095 0.093 0.092 0.091 0.090 0.089 0.083 0.087 0.090 0.093 0.095 0.097 0.098 0.100 0.101 0.102 0.103 0.142 0.140 0.138 0.136 0.134 0.132 0.130 0.129 0.127 0.126 0.125 0.083 0.088 0.091 0.095 0.098 0.100 0.102 0.104 0.106 0.108 0.109 0.224 0.224 0.224 0.223 0.222 0.220 0.219 0.217 0.216 0.214 0.213 0.075 0.080 0.084 0.089 0.093 0.096 0.099 0.102 0.105 0.108 0.110 0.285 0.288 0.290 0.292 0.292 0.292 0.292 0.292 0.291 0.290 0.289 0.064 0.069 0.074 0.078 0.083 0.086 0.090 0.094 0.097 0.100 0.102 0.363 0.372 0.379 0.384 0.389 0.393 0.396 0.398 0.400 0.401 0.402 0.048 0.052 0.056 0.060 0.064 0.068 0.071 0.075 0.078 0.081 0.084 0.408 0.421 0.431 0.440 0.448 0.455 0.460 0.465 0.469 0.473 0.476 0.037 0.041 0.044 0.048 0.051 0.054 0.057 0.060 0.063 0.066 0.069 0.437 0.452 0.465 0.477 0.487 0.496 0.503 0.510 0.516 0.522 0.526 0.031 0.034 0.036 0.039 0.042 0.045 0.048 0.050 0.053 0.055 0.058 0.457 0.474 0.489 0.502 0.514 0.524 0.534 0.542 0.550 0.557 0.563 0.026 0.028 0.031 0.033 0.036 0.038 0.040 0.043 0.045 0.047 0.050 0.471 0.490 0.506 0.520 0.533 0.545 0.556 0.566 0.575 0.583 0.590 0.022 0.024 0.027 0.029 0.031 0.033 0.035 0.037 0.039 0.041 0.043 0.482 0.502 0.519 0.534 0.549 0.561 0.573 0.584 0.594 0.602 0.611 0.020 0.022 0.023 0.025 0.027 0.029 0.031 0.033 0.035 0.036 0.038 0.491 0.511 0.529 0.545 0.560 0.574 0.587 0.598 0.609 0.618 0.627 0.017 0.019 0.021 0.023 0.024 0.026 0.028 0.029 0.031 0.033 0.034 0.498 0.519 0.537 0.554 0.570 0.584 0.597 0.610 0.621 0.631 0.641 0.016 0.017 0.019 0.020 0.022 0.023 0.025 0.027 0.028 0.030 0.031 0.529 0.553 0.575 0.595 0.614 0.631 0.647 0.662 0.677 0.690 0.702 0.008 0.009 0.010 0.010 0.011 0.012 0.013 0.013 0.014 0.015 0.016 0.560 0.587 0.612 0.635 0.656 0.677 0.696 0.714 0.731 0.748 0.763 0.000 0.000 0.000 0.000 0.000 0.000 0.001 0.001 0.001 0.001 0.001 TABLE 3.1(cont.) Values of I, and I₂ (N =H/B' and M = L/B) N M=2.5 4.0 5.0 6.0 7.0 8.0 9.0 10.0 25.0 50.0 100.0 0.2 % = 0.007 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.043 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.4 70 90 0.6 80 0.8 1.0 15 15 2.0 20 3.0 00 4.0 5.0 6.0 7.0 70 8.0 9.0 96 10.0 20.0 500.0 2 0.026 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.074 0.075 0.075 0.075 0.076 0.076 0.076 0.076 0.076 0.076 0.076 0.053 0.051 0.050 0.050 0.050 0.049 0.049 0.049 0.049 0.049 0.049 0.094 0.097 0.097 0.098 0.098 0.098 0.098 0.098 0.098 0.098 0.098 0.086 0.082 0.081 0.080 0.080 0.080 0.079 0.079 0.079 0.079 0.079 0.107 0.111 0.112 0.113 0.113 0.113 0.113 0.114 0.114 0.114 0.114 0.121 0.115 0.113 0.112 0.112 0.112 0.111 0.111 0.110 0.110 0.110 0.114 0.120 0.122 0.123 0.123 0.124 0.124 0.124 0.125 0.125 0.125 0.207 0.197 0.194 0.192 0.191 0.190 0.190 0.189 0.188 0.188 0.188 0.118 0.130 0.134 0.136 0.137 0.138 0.138 0.139 0.140 0.140 0.140 0.284 0.271 0.267 0.264 0.262 0.261 0.260 0.259 0.257 0.256 0.256 0.114 0.131 0.136 0.139 0.141 0.143 0.144 0.145 0.147 0.147 0.148 0.402 0.392 0.386 0.382 0.378 0.376 0.374 0.373 0.368 0.367 0.367 0.097 0.122 0.131 0.137 0.141 0.144 0.145 0.147 0.152 0.153 0.154 0.484 0.484 0.479 0.474 0.470 0.466 0.464 0.462 0.453 0.451 0.451 0.082 0.110 0.121 0.129 0.135 0.139 0.142 0.145 0.154 0.155 0.156 0.553 0.554 0.552 0.548 0.543 0.540 0.536 0.534 0.522 0.519 0.519 0.070 0.098 0.111 0.120 0.128 0.133 0.137 0.140 0.154 0.156 0.157 0.585 0.609 0.610 0.608 0.604 0.601 0.598 0.595 0.579 0.576 0.575 0.060 0.087 0.101 0.111 0.120 0.126 0.131 0.135 0.153 0.157 0.157 0.618 0.653 0.658 0.658 0.656 0.653 0.650 0.647 0.628 0.624 0.623 0.053 0.078 0.092 0.103 0.112 0.119 0.125 0.129 0.152 0.157 0.158 0.643 0.688 0.697 0.700 0.700 0.698 0.695 0.692 0.672 0.666 0.665 0.047 0.071 0.084 0.095 0.104 0.112 0.118 0.124 0.151 0.156 0.158 0.663 0.716 0.730 0.736 0.737 0.736 0.735 0.732 0.710 0.704 0.702 0.042 0.064 0.077 0.088 0.097 0.105 0.112 0.118 0.149 0.156 0.158 0.679 0.740 0.758 0.766 0.770 0.770 0.770 0.768 0.745 0.738 0.735 0.038 0.059 0.071 0.082 0.091 0.099 0.106 0.112 0.147 0.156 0.158 0.756 0.856 0.896 0.925 0.945 0.959 0.969 0.977 0.982 0.965 0.957 0.020 0.031 0.039 0.046 0.053 0.059 0.065 0.071 0.124 0.148 0.156 0.832 0.977 1.046 1.102 1.150 1.191 1.227 1.259 1.532 1.721 1.879 0.001 0.001 0.002 0.002 0.002 0.003 0.003 0.003 0.008 0.016 0.031 Useful equations: The modulus of elasticity of granular soil (Es) is an important parameter in estimating the elastic settlement of foundations. It can be estimated as: where Pa= atmospheric pressure (=100 kN/m²) a= 5 for sand with fines E₁ = apa№60 a= 10 for clear normally consolidated sand a= 15 for clean overconsolidated sand. A reinforced concrete circular column is supported by a square isolated footing (reinforced concrete spread footing). Net allowable soil pressure: net qa = 130 kPa Column loads (unfactored): D=170 kN, L = 110 kN Column diameter = 320 mm Column steel: six No. 25 bars; fy = 420 MPa, Esteel=200000 Mpa Column concrete: f=26MPa Footing concrete: f = 20MPa Required: 1- determine the dimension and the thickness of footing TABLE 3.1 Values of I, and I2 (N =H/B' and M = L/B) N M=1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 0.2 1, 0.009 0.008 0.008 0.008 0.008 0.008 0.007 0.007 0.007 0.007 0.007 12 0.041 0.042 0.042 0.042 0.042 0.042 0.043 0.043 0.043 0.043 0.043 0.4 90 0.6 0.8 1.0 1.5 2.0 3.0 4.0 5.0 6.0 7.0 00 8.0 9.0 10.0 20.0 500.0 0.033 0.032 0.031 0.030 0.029 0.028 0.028 0.027 0.027 0.027 0.027 0.066 0.068 0.069 0.070 0.070 0.071 0.071 0.072 0.072 0.073 0.073 0.066 0.064 0.063 0.061 0.060 0.059 0.058 0.057 0.056 0.056 0.055 0.079 0.081 0.083 0.085 0.087 0.088 0.089 0.090 0.091 0.091 0.092 0.104 0.102 0.100 0.098 0.096 0.095 0.093 0.092 0.091 0.090 0.089 0.083 0.087 0.090 0.093 0.095 0.097 0.098 0.100 0.101 0.102 0.103 0.142 0.140 0.138 0.136 0.134 0.132 0.130 0.129 0.127 0.126 0.125 0.083 0.088 0.091 0.095 0.098 0.100 0.102 0.104 0.106 0.108 0.109 0.224 0.224 0.224 0.223 0.222 0.220 0.219 0.217 0.216 0.214 0.213 0.075 0.080 0.084 0.089 0.093 0.096 0.099 0.102 0.105 0.108 0.110 0.285 0.288 0.290 0.292 0.292 0.292 0.292 0.292 0.291 0.290 0.289 0.064 0.069 0.074 0.078 0.083 0.086 0.090 0.094 0.097 0.100 0.102 0.363 0.372 0.379 0.384 0.389 0.393 0.396 0.398 0.400 0.401 0.402 0.048 0.052 0.056 0.060 0.064 0.068 0.071 0.075 0.078 0.081 0.084 0.408 0.421 0.431 0.440 0.448 0.455 0.460 0.465 0.469 0.473 0.476 0.037 0.041 0.044 0.048 0.051 0.054 0.057 0.060 0.063 0.066 0.069 0.437 0.452 0.465 0.477 0.487 0.496 0.503 0.510 0.516 0.522 0.526 0.031 0.034 0.036 0.039 0.042 0.045 0.048 0.050 0.053 0.055 0.058 0.457 0.474 0.489 0.502 0.514 0.524 0.534 0.542 0.550 0.557 0.563 0.026 0.028 0.031 0.033 0.036 0.038 0.040 0.043 0.045 0.047 0.050 0.471 0.490 0.506 0.520 0.533 0.545 0.556 0.566 0.575 0.583 0.590 0.022 0.024 0.027 0.029 0.031 0.033 0.035 0.037 0.039 0.041 0.043 0.482 0.502 0.519 0.534 0.549 0.561 0.573 0.584 0.594 0.602 0.611 0.020 0.022 0.023 0.025 0.027 0.029 0.031 0.033 0.035 0.036 0.038 0.491 0.511 0.529 0.545 0.560 0.574 0.587 0.598 0.609 0.618 0.627 0.017 0.019 0.021 0.023 0.024 0.026 0.028 0.029 0.031 0.033 0.034 0.498 0.519 0.537 0.554 0.570 0.584 0.597 0.610 0.621 0.631 0.641 0.016 0.017 0.019 0.020 0.022 0.023 0.025 0.027 0.028 0.030 0.031 0.529 0.553 0.575 0.595 0.614 0.631 0.647 0.662 0.677 0.690 0.702 0.008 0.009 0.010 0.010 0.011 0.012 0.013 0.013 0.014 0.015 0.016 0.560 0.587 0.612 0.635 0.656 0.677 0.696 0.714 0.731 0.748 0.763 0.000 0.000 0.000 0.000 0.000 0.000 0.001 0.001 0.001 0.001 0.001 TABLE 3.1(cont.) Values of I, and I₂ (N =H/B' and M = L/B) N M=2.5 4.0 5.0 6.0 7.0 8.0 9.0 10.0 25.0 50.0 100.0 0.2 % = 0.007 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.006 0.043 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.044 0.4 70 90 0.6 80 0.8 1.0 15 15 2.0 20 3.0 00 4.0 5.0 6.0 7.0 70 8.0 9.0 96 10.0 20.0 500.0 2 0.026 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.024 0.074 0.075 0.075 0.075 0.076 0.076 0.076 0.076 0.076 0.076 0.076 0.053 0.051 0.050 0.050 0.050 0.049 0.049 0.049 0.049 0.049 0.049 0.094 0.097 0.097 0.098 0.098 0.098 0.098 0.098 0.098 0.098 0.098 0.086 0.082 0.081 0.080 0.080 0.080 0.079 0.079 0.079 0.079 0.079 0.107 0.111 0.112 0.113 0.113 0.113 0.113 0.114 0.114 0.114 0.114 0.121 0.115 0.113 0.112 0.112 0.112 0.111 0.111 0.110 0.110 0.110 0.114 0.120 0.122 0.123 0.123 0.124 0.124 0.124 0.125 0.125 0.125 0.207 0.197 0.194 0.192 0.191 0.190 0.190 0.189 0.188 0.188 0.188 0.118 0.130 0.134 0.136 0.137 0.138 0.138 0.139 0.140 0.140 0.140 0.284 0.271 0.267 0.264 0.262 0.261 0.260 0.259 0.257 0.256 0.256 0.114 0.131 0.136 0.139 0.141 0.143 0.144 0.145 0.147 0.147 0.148 0.402 0.392 0.386 0.382 0.378 0.376 0.374 0.373 0.368 0.367 0.367 0.097 0.122 0.131 0.137 0.141 0.144 0.145 0.147 0.152 0.153 0.154 0.484 0.484 0.479 0.474 0.470 0.466 0.464 0.462 0.453 0.451 0.451 0.082 0.110 0.121 0.129 0.135 0.139 0.142 0.145 0.154 0.155 0.156 0.553 0.554 0.552 0.548 0.543 0.540 0.536 0.534 0.522 0.519 0.519 0.070 0.098 0.111 0.120 0.128 0.133 0.137 0.140 0.154 0.156 0.157 0.585 0.609 0.610 0.608 0.604 0.601 0.598 0.595 0.579 0.576 0.575 0.060 0.087 0.101 0.111 0.120 0.126 0.131 0.135 0.153 0.157 0.157 0.618 0.653 0.658 0.658 0.656 0.653 0.650 0.647 0.628 0.624 0.623 0.053 0.078 0.092 0.103 0.112 0.119 0.125 0.129 0.152 0.157 0.158 0.643 0.688 0.697 0.700 0.700 0.698 0.695 0.692 0.672 0.666 0.665 0.047 0.071 0.084 0.095 0.104 0.112 0.118 0.124 0.151 0.156 0.158 0.663 0.716 0.730 0.736 0.737 0.736 0.735 0.732 0.710 0.704 0.702 0.042 0.064 0.077 0.088 0.097 0.105 0.112 0.118 0.149 0.156 0.158 0.679 0.740 0.758 0.766 0.770 0.770 0.770 0.768 0.745 0.738 0.735 0.038 0.059 0.071 0.082 0.091 0.099 0.106 0.112 0.147 0.156 0.158 0.756 0.856 0.896 0.925 0.945 0.959 0.969 0.977 0.982 0.965 0.957 0.020 0.031 0.039 0.046 0.053 0.059 0.065 0.071 0.124 0.148 0.156 0.832 0.977 1.046 1.102 1.150 1.191 1.227 1.259 1.532 1.721 1.879 0.001 0.001 0.002 0.002 0.002 0.003 0.003 0.003 0.008 0.016 0.031 Useful equations: The modulus of elasticity of granular soil (Es) is an important parameter in estimating the elastic settlement of foundations. It can be estimated as: where Pa= atmospheric pressure (=100 kN/m²) a= 5 for sand with fines E₁ = apa№60 a= 10 for clear normally consolidated sand a= 15 for clean overconsolidated sand.
Expert Answer:
Answer rating: 100% (QA)
Solution Step1 NOW THE ANSWER IS How to Determine the Bearing Capacity The specified value for the net permitted soil pressure is 130 kPa This is the ... View the full answer
Related Book For
Introduction to Java Programming, Comprehensive Version
ISBN: 978-0133761313
10th Edition
Authors: Y. Daniel Liang
Posted Date:
Students also viewed these programming questions
-
Using any means at your disposal (MS Word, MS Paint, Adobe Photoshop, or hand drawn, etc.), draw a flowchart that will let the user enter 1000 numbers. The program will identify the lowest number...
-
Let A, B be sets. Define: (a) the Cartesian product (A B) (b) the set of relations R between A and B (c) the identity relation A on the set A [3 marks] Suppose S, T are relations between A and B, and...
-
A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere...
-
Delta Machine Company purchased a computerized assembly machine for $135,000 on January 1, 2018. Delta Machine Company estimated that the machine would have a life of four years and a $25,000 salvage...
-
Numismatic Funding Corporation (Numismatic), with its principal place of business in New York, sells rare and collector coins by mail throughout the United States. Frederick R. Prewitt, a resident of...
-
Larry Riley formed a rental agreement for a self-storage unit with Iron Gate Self Storage in December 2003. The agreement stated that a maximum of \($5,000\) of personal property could be stored in...
-
Depreciation and Cash Flow Ohare Companys only asset as of January 1, 2010, was a limousine. During 2010, only the following three transactions occurred: Services of $100,000 were provided on...
-
Consider the following Closed-loop block diagram of a system: R(s) K s + 5 15 Y(s) s+ p Consider the following parameter values: p = 2 and K-10. a. Obtain the closed-loop transfer function for the...
-
Business Plan You have been reading and learning about entrepreneurship and small business management throughout the semester. These topics relate well to a simple business plan that you will create...
-
Reccomendation of Zitcong case study What factors (e .g ., stakeholders, timelines, underlying issues) should be considered in developing a recommendation? What recommendation(s) are you making? Tell...
-
For technical support services business: 1. what can be the target customers and marketing mix, the demographics this plan will target, geographic area, age, etc. 2. product/services - types and...
-
Directions: Read the article carefully and answer the question thoroughly. A look at donor and estate taxes SIR Benjamin Franklin wrote: "... but in this world, nothing can be said to be certain,...
-
R. v. Haevischer, 2023 SCC 11. This is a case dealing with the police conduct and conditions of pre-trial confinement which the accused believed amountd to an abuse of process. Who wrote the judgment...
-
Stan promised his favorite nephew Ned that he would leave his farm to Ned if Ned would live with him and tend to the farm for the rest of Stan's life. Ned did so, providing services to Stan that were...
-
14. All of the following are common modal annuitization payout options EXCEPT: a. lump-sum b. monthly c. quarterly d. annually
-
Nike manufactures shoes and sportswear. How has the Internet changed the way this company communicates with its suppliers and retail customers?
-
Write a program that fills in table names in a combo box, as shown in Figure 32.30b. You can select a table from the combo box to display its contents in the text area. Table Name enrollment Show...
-
Write a program that prompts the user to enter a string and displays the number of the uppercase letters in the string. Enter a string: Welcome to Java The number of uppercase letters is 2 -Enter
-
A university posts its employees salaries at http://cs.armstrong.edu/liang/data/Salary.txt. Each line in the file consists of a faculty members first name, last name, rank, and salary (see...
-
Construct a frequency and relative frequency histogram of the five-year rate of- return data discussed in Example 3. Approach To draw the frequency histogram, use the frequency distribution in Table...
-
Construct a frequency and relative frequency histogram of the five-year rate of- return data discussed in Example 3. Approach We will use StatCrunch to construct the frequency and relative frequency...
-
The data in Table 14 represent the two-year average percentage of persons living in poverty, by state, for the years 20122013. Draw a stem-and-leaf plot of the data. Approach Step 1 Treat the integer...
Study smarter with the SolutionInn App