N = 164

Blue-eyed children = 80

Brown-eyed children = 84

1. It is a random sample and representative of other schools in the same population.

1. 2. In a study of 164 students, determine a confidence interval of 95% for the proportions of blue-eyed children (brown-eyed children) in the population.
2. Using the 95% confidence interval, conclude if we can believe there is an equal proportion of blue-eyed children as brown-eyed children in the target population.