Name: 11111111 11111 ID: C Scenario K An agricultural researcher wishes to see if a kelp...
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Name: 11111111 11111 ID: C Scenario K An agricultural researcher wishes to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost in the autumn, 12 of the 50 plants in group 1 exhibited damage, and 18 of the 50 plants in group 2 showed damage. Let p be the actual proportion of all tomato plants of this variety that would experience damage under the kelp treatment, and let p be the actual proportion of all tomato plants of this variety that would experience damage under the no-kelp treatment, assuming that the tomatoes are grown under conditions similar to those in the experiment. 17. Use Scenario K. A 99% confidence interval for pi-p2 is A. (-0.142,-0.098) B. (-0.298,0.058) c. (-0.30,0.06) D. (-0.354,0.114) E. (-0.36,0.12) Name: 11111111 11111 ID: C Scenario K An agricultural researcher wishes to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost in the autumn, 12 of the 50 plants in group 1 exhibited damage, and 18 of the 50 plants in group 2 showed damage. Let p be the actual proportion of all tomato plants of this variety that would experience damage under the kelp treatment, and let p be the actual proportion of all tomato plants of this variety that would experience damage under the no-kelp treatment, assuming that the tomatoes are grown under conditions similar to those in the experiment. 17. Use Scenario K. A 99% confidence interval for pi-p2 is A. (-0.142,-0.098) B. (-0.298,0.058) c. (-0.30,0.06) D. (-0.354,0.114) E. (-0.36,0.12)
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