?(n=o to ?) 1/[(sqrt(2)^n] so I found that it was convergent because according to geometricseries test r=
Fantastic news! We've Found the answer you've been seeking!
Question:
so I found that it was convergent because according to geometricseries test r= 1/sqrt2 which is less than one, so itconverges.
because it converges, what is the sum of the series?
THANKS!!!!!!!!!!!
Related Book For
Managerial Accounting An Integrative Approach
ISBN: 9780999500491
2nd Edition
Authors: C J Mcnair Connoly, Kenneth Merchant
Posted Date: