Often it is necessary to validate data input by the user and repeat the request for...

 

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Often it is necessary to validate data input by the user and repeat the request for the data in the case where the input of the user is not valid. This can be done by using a do loop, while loop, or for loop See the Lab04 04 example Assign 4.1(Lab04_01) Make a program from the following checkpoint if you cannot do it see solution. Checkpoint 4.1 What will the following program segments display? a) x = 2; y = x++; System.out.println(y); b) x = 2; System.out.println(x++); c) x = 2; System.out.println(--x); d) x = 8; y = x--; System.out.println(y); Solution: } Make a program from the following checkpoint if you cannot do it see Solution. 4.4 Write an input validation loop that asks the user to enter a number in the range of 10 through 24. public class Lab04_01 public static void main(String[] args) { { int x; Solution: int y; x-2; yx++; System.out.println(y); x = 2; System.out.println(x++); x=2; System.out.println(--x); x-8; y-x--; System.out.println(y); public class Lab4_04 //program name is case sensitive { public static void main(String[] args) { int num=15; while (num>=10 &&num<=24) { System.out.println(" number you is in the range 10 to 24"); break; } Modify the above program to read the number from keyboard. Add only the yellow lines to your Lab4_4 program. Page< 2 > of 6 C ZOOM + import java.util.Scanner; public class Lab4_04x //program name is case sensitive { public static void main(String[] args) { System.out.println("Enter a number between 10 to 24"); Scanner inNum = new Scanner(System.in); int num-inNum.nextInt(); while (num>=10 &&num<=24) { System.out.println(" number you is in the range 10 to 24"); break; } }L } Make a single program from assign4.5 and 4.6 to, if you cannot do it see the Solution 4.5 Write an input validation loop that asks the user to enter "y", "y", "N", or "n" 4.6 Write an input validation loop that asks the user to enter "Yes" or "No" Solution: public class Lab04 05 06 { public static void main(String[] args) { String str="n"; while (stria || str !="y") Assign4.5 System.out.println("You did not enter Y or y, you enter "+str): break; String stri=; while (strl!="Yes" || strl !="No") Assign4.6 System.out.println("You did not enter Yes or No, you enter "+strl); break; } } Page< 3 > of 6 C ZOOM + import java.util.Scanner; public class Assign4_5 { { public static void main(String[] args) Scanner keyboard = new Scanner(System.in); System.out.print("Enter a Y or y: "); String str keyboard.nextLine(); // read the first line char ch1 str.charAt(0); // read the first character of str string. while(chl='Y' || ch₁ =='y') L// Compar the ch1 with y or Y {{//if expression is true, print the blow line and break the loop System.out.println("You enter Y or y "+str); break; } Assign4_5.java Compile Messages GRASP Messages Run I/O Interactions Enter a Y or y: y End You enter Y or y, you enter y Clear ----jGRASP: operation complete. import java.util.Scanner; public class Assign4_5 public static void main(String[] args) { { Scanner keyboard = new Scanner(System.in); System.out.print ("Enter a Y or y: "); String str = keyboard.nextLine(); // read the first line from input char ch1 = str.charAt(0); character of str string. // read the first the chl with while ( ch1=='Y' || ch1 =='y') // compare y or Y {//if expression is true, print the blow line and break the loop System.out.println("You enter Y or y "+str); break; } Page< 4 > of 6 C ZOOM + } Optimal: If you have extra time, please practice the following. no credit If you have extra time use the Scanner keyboard= new Scanner(System.in); by declare and using the import java.util.Scanner; Assin4.1 to 4.6 using Scanner import to read in from keyboard by the API import java.util.Scanner; on the header file Inside the main usage. int num=0; Scanner keyboard= new Scanner(System.in); System.out.print("Enter a number between 10to 28: "); num = keyboard.nextInt(); Here is complete program screenshot, the checkpoint 4.1 to 4.6: Page< 5 > of 6 C ZOOM + import java.util.Scanner; public class Assig4_1To_4_6 public static void main(String[] args) { { int x =2; int y =x++; System.out.println(y); x=2; System.out.println(x++); x=2; System.out.println(--x); x=8; y =x--; System.out.println(y); int num=1; Scanner keyboard= new Scanner(System.in); System.out.print("Enter a number betweeb 10to 28: "); num = keyboard.nextInt(); while(num >=10 && num <=24) } System.out.println("You enter a number between 10 to 24 you enter "+num); break; keyboard= new Scanner(System.in); System.out.print("Enter a Y or y: "); String str keyboard.nextLine(); while(str=="Y" || str =="y") { } System.out.println("You enter Y or y, you enter "+str); break; keyboard= new Scanner(System.in); System.out.print("Enter a Yes or No: "); String str1=keyboard.nextLine(); while(stri== "Yes" || str1 == "No") { System.out.println("You enter Yes or No, you enter "+str1); break; } Page< 6 > of 6 C ZOOM + Often it is necessary to validate data input by the user and repeat the request for the data in the case where the input of the user is not valid. This can be done by using a do loop, while loop, or for loop See the Lab04 04 example Assign 4.1(Lab04_01) Make a program from the following checkpoint if you cannot do it see solution. Checkpoint 4.1 What will the following program segments display? a) x = 2; y = x++; System.out.println(y); b) x = 2; System.out.println(x++); c) x = 2; System.out.println(--x); d) x = 8; y = x--; System.out.println(y); Solution: } Make a program from the following checkpoint if you cannot do it see Solution. 4.4 Write an input validation loop that asks the user to enter a number in the range of 10 through 24. public class Lab04_01 public static void main(String[] args) { { int x; Solution: int y; x-2; yx++; System.out.println(y); x = 2; System.out.println(x++); x=2; System.out.println(--x); x-8; y-x--; System.out.println(y); public class Lab4_04 //program name is case sensitive { public static void main(String[] args) { int num=15; while (num>=10 &&num<=24) { System.out.println(" number you is in the range 10 to 24"); break; } Modify the above program to read the number from keyboard. Add only the yellow lines to your Lab4_4 program. Page< 2 > of 6 C ZOOM + import java.util.Scanner; public class Lab4_04x //program name is case sensitive { public static void main(String[] args) { System.out.println("Enter a number between 10 to 24"); Scanner inNum = new Scanner(System.in); int num-inNum.nextInt(); while (num>=10 &&num<=24) { System.out.println(" number you is in the range 10 to 24"); break; } }L } Make a single program from assign4.5 and 4.6 to, if you cannot do it see the Solution 4.5 Write an input validation loop that asks the user to enter "y", "y", "N", or "n" 4.6 Write an input validation loop that asks the user to enter "Yes" or "No" Solution: public class Lab04 05 06 { public static void main(String[] args) { String str="n"; while (stria || str !="y") Assign4.5 System.out.println("You did not enter Y or y, you enter "+str): break; String stri=; while (strl!="Yes" || strl !="No") Assign4.6 System.out.println("You did not enter Yes or No, you enter "+strl); break; } } Page< 3 > of 6 C ZOOM + import java.util.Scanner; public class Assign4_5 { { public static void main(String[] args) Scanner keyboard = new Scanner(System.in); System.out.print("Enter a Y or y: "); String str keyboard.nextLine(); // read the first line char ch1 str.charAt(0); // read the first character of str string. while(chl='Y' || ch₁ =='y') L// Compar the ch1 with y or Y {{//if expression is true, print the blow line and break the loop System.out.println("You enter Y or y "+str); break; } Assign4_5.java Compile Messages GRASP Messages Run I/O Interactions Enter a Y or y: y End You enter Y or y, you enter y Clear ----jGRASP: operation complete. import java.util.Scanner; public class Assign4_5 public static void main(String[] args) { { Scanner keyboard = new Scanner(System.in); System.out.print ("Enter a Y or y: "); String str = keyboard.nextLine(); // read the first line from input char ch1 = str.charAt(0); character of str string. // read the first the chl with while ( ch1=='Y' || ch1 =='y') // compare y or Y {//if expression is true, print the blow line and break the loop System.out.println("You enter Y or y "+str); break; } Page< 4 > of 6 C ZOOM + } Optimal: If you have extra time, please practice the following. no credit If you have extra time use the Scanner keyboard= new Scanner(System.in); by declare and using the import java.util.Scanner; Assin4.1 to 4.6 using Scanner import to read in from keyboard by the API import java.util.Scanner; on the header file Inside the main usage. int num=0; Scanner keyboard= new Scanner(System.in); System.out.print("Enter a number between 10to 28: "); num = keyboard.nextInt(); Here is complete program screenshot, the checkpoint 4.1 to 4.6: Page< 5 > of 6 C ZOOM + import java.util.Scanner; public class Assig4_1To_4_6 public static void main(String[] args) { { int x =2; int y =x++; System.out.println(y); x=2; System.out.println(x++); x=2; System.out.println(--x); x=8; y =x--; System.out.println(y); int num=1; Scanner keyboard= new Scanner(System.in); System.out.print("Enter a number betweeb 10to 28: "); num = keyboard.nextInt(); while(num >=10 && num <=24) } System.out.println("You enter a number between 10 to 24 you enter "+num); break; keyboard= new Scanner(System.in); System.out.print("Enter a Y or y: "); String str keyboard.nextLine(); while(str=="Y" || str =="y") { } System.out.println("You enter Y or y, you enter "+str); break; keyboard= new Scanner(System.in); System.out.print("Enter a Yes or No: "); String str1=keyboard.nextLine(); while(stri== "Yes" || str1 == "No") { System.out.println("You enter Yes or No, you enter "+str1); break; } Page< 6 > of 6 C ZOOM +

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