On a cool spring morning (T = 7.7 oC), a mechanic inflates a customer's tires to the manufacturer's recommended pressure of 30.2 PSI. That afternoon, the temperature unexpectedly soars to 25 oC. Assuming there is no change in the volume of the tires, determine the pressure in the tires in the afternoon. Give your answer in PSI. (1 PSI = 6894.76 Pa)  

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Sure here is the solution to the problem Step 1 Convert the temperatures to Kelvin To use the ideal ... View the full answer