A composite horizontal curve consisting of entry and exit transition curves of equal length and a...
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A composite horizontal curve consisting of entry and exit transition curves of equal length and a central circular arc is to connect two straights on a new road, which intersect at a point I. The design speed for the road is 70 kph, the radius of the central circular arc is 510 m and the rate of change of radial acceleration is 0.30 m s-3. The through chainage of I is 3196.23 m and the deflection angle is 10°17'46". The coordinates of point I are (596.39 mE, 622.45 mN) and the bearing from the entry tangent point T to point I is 102°35'28". Pegs are to be placed on the centre line at exact 20 m multiples of through chainage. Calculate the through chainages and the coordinates of all the points that are to be set out on the curve. A composite horizontal curve consisting of entry and exit transition curves of equal length and a central circular arc is to connect two straights on a new road, which intersect at a point I. The design speed for the road is 70 kph, the radius of the central circular arc is 510 m and the rate of change of radial acceleration is 0.30 m s-3. The through chainage of I is 3196.23 m and the deflection angle is 10°17'46". The coordinates of point I are (596.39 mE, 622.45 mN) and the bearing from the entry tangent point T to point I is 102°35'28". Pegs are to be placed on the centre line at exact 20 m multiples of through chainage. Calculate the through chainages and the coordinates of all the points that are to be set out on the curve.
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Answer rating: 100% (QA)
SOLUTION To calculate the through chainages and coordinates of the points on the curve we can use the following steps Step 1 Calculate the length of the central circular arc The length of the central ... View the full answer
Related Book For
Accounting concepts and applications
ISBN: 978-0538745482
11th Edition
Authors: Albrecht Stice, Stice Swain
Posted Date:
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