PERFORM A CHI-SQUARE GOODNESS OF FIT: The Hoosier Lottery scratch-off game titled Lady Luck costs $5.00...

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PERFORM A CHI-SQUARE GOODNESS OF FIT: The Hoosier Lottery scratch-off game titled "Lady Luck" costs $5.00 and, according to hoosierlottery.com, has a 1 in 3.94 odds of winning. Imagine we bought 10 of these scratch-off tickets. Follow the steps below to perform a Chi-Square Goodness of Fit test to say whether we won as many times as you'd expect based on the published odds of winning. 7. Based on the advertised 1 in 3.94 odds of winning, how many of the 10 games purchased would you expect to be winners and how many would you expect to be losers (i.e, what is our "expected count" for number of winning cards and losing cards)? Do not round to whole numbers. Expected count for winning scratch-offs: Expected count for losing scratch-offs: 8. Imagine we scratch off all 10 games and find that only 1 card is a winner and 9 cards were not. Is the Hoosier Lottery lying about the odds of winning? Use the expected counts (obtained above) with the observed counts (provided here) to solve for x using the formula below. Circle your final answer (obtained x). x = [(0 - E)] E 9. Use the formula below to calculate the effect size (Phi, D) of this x. $ = 10. Would you describe the size of this effect as small, medium, or large? a. Small b. Medium C. Large PERFORM A CHI-SQUARE GOODNESS OF FIT: The Hoosier Lottery scratch-off game titled "Lady Luck" costs $5.00 and, according to hoosierlottery.com, has a 1 in 3.94 odds of winning. Imagine we bought 10 of these scratch-off tickets. Follow the steps below to perform a Chi-Square Goodness of Fit test to say whether we won as many times as you'd expect based on the published odds of winning. 7. Based on the advertised 1 in 3.94 odds of winning, how many of the 10 games purchased would you expect to be winners and how many would you expect to be losers (i.e, what is our "expected count" for number of winning cards and losing cards)? Do not round to whole numbers. Expected count for winning scratch-offs: Expected count for losing scratch-offs: 8. Imagine we scratch off all 10 games and find that only 1 card is a winner and 9 cards were not. Is the Hoosier Lottery lying about the odds of winning? Use the expected counts (obtained above) with the observed counts (provided here) to solve for x using the formula below. Circle your final answer (obtained x). x = [(0 - E)] E 9. Use the formula below to calculate the effect size (Phi, D) of this x. $ = 10. Would you describe the size of this effect as small, medium, or large? a. Small b. Medium C. Large