please do 35-43thank you A. Hydrochloric Acid Solutions 1. Original concentration HCl: 0.1M 3. Volume HCl used

please do 35-43thank you

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A. Hydrochloric Acid Solutions 1. Original concentration HCl: 0.1M 3. Volume HCl used in dilution: 5.00 mL B. Acetic Acid Solutions 5. Original conc. CH3CO₂H 7. Volume CH3CO2H used C. Buffer Solutions 9. Mass of CH3CO2Na used 11. Volume of CH3CO2H used 8.5 13. Total volume of buffer solution 16. Beaker A 17. Beaker B 18. Beaker C 19. Beaker D 0.1 4.63 5.00 4.45 4.10 4.60 14. Volume of 6 M HCl used for addition to beaker A: 15. Volume of 6 M NaOH used for addition to beaker C: 4.45 M 6. pH of original CH3CO₂H soln mL 8. pH of diluted CH3CO2H soln 2. pH of original HCl solution: 1.47 4. pH of diluted HCl solution: 2.11 mL Initial pH of Solutions pH of Solutions after additions 100 g 10. Original concentration CH3CO₂H 6 M 12. Volume of distilled water used 1.30 4.12 mL 2.96 4.38 1.0 1.0 mL; beaker B: 2.85 mL; beaker D: 3.68 91.5 mL 1.0 1.0 mL mL A. Hydrochloric Acid Solutions 1. Original concentration HCl: 0.1M 3. Volume HCl used in dilution: 5.00 mL B. Acetic Acid Solutions 5. Original conc. CH3CO₂H 7. Volume CH3CO2H used C. Buffer Solutions 9. Mass of CH3CO2Na used 11. Volume of CH3CO2H used 8.5 13. Total volume of buffer solution 16. Beaker A 17. Beaker B 18. Beaker C 19. Beaker D 0.1 4.63 5.00 4.45 4.10 4.60 14. Volume of 6 M HCl used for addition to beaker A: 15. Volume of 6 M NaOH used for addition to beaker C: 4.45 M 6. pH of original CH3CO₂H soln mL 8. pH of diluted CH3CO2H soln 2. pH of original HCl solution: 1.47 4. pH of diluted HCl solution: 2.11 mL Initial pH of Solutions pH of Solutions after additions 100 g 10. Original concentration CH3CO₂H 6 M 12. Volume of distilled water used 1.30 4.12 mL 2.96 4.38 1.0 1.0 mL; beaker B: 2.85 mL; beaker D: 3.68 91.5 mL 1.0 1.0 mL mL

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The detailed answer for the above question is provided below Answer 35 The pH of beaker C after the addition of 6 M NaOH is 13 The pH of a solution is a measure of its acidity or alkalinity A pH of 7 ... View the full answer