please someone help me solve Question 3 :you'll be needing these informations below of question 2 to answer question 3 i think:

answers of question 2 :

Question 3 Please note that the specifications for the plastic tubes of problem 2 above are from: 84.5 cm - 87 cm. Based on the information available, estimate the percentage of plastic tubes which will respect the announced limits. Question 2 : We want to control a process for cutting plastic tubes, with a nominal length of 85 cm. Ten samples of 6 tubes each are taken (see table). Draw the control charts relevant: calculate the control limits for this process, place the points accordingly on the cards and determine if the process is under control. Pre di chent ent X X2 X3 X4 X6 84,2 84 86,5 2 3 84,7 83,2 84,4 4 85,2 83,4 86,3 86,8 86,7 85,4 85,1 86,3 84,1 84,4 86,2 83,5 86 85,4 83,1 84.2 83,3 84,3 84,8 86,8 86,8 83,3 84,6 X 85,7 86,8 84,1 86,8 83,6 85,1 84,5 85,5 83,3 84,5 5 83,4 6 84,2 85,5 86 7 8 84,3 85 84,8 84,8 84,9 9 86,5 86,3 85,7 83,9 85,3 84,2 84,8 83,7 86,6 84,9 10 85,8 86,9 # SAMPLE 1 2 3 4 5 6 AVERAGE RANGE 1 85.2 84.2 84.1 84.2 85.7 84 84.57 1.7 2 83.4 83.3 84.4 84.7 86.8 86.5 84.85 3.5 3 86.3 84.3 86.2 83.2 84.1 84.4 84.75 3.1 4 86.8 84.8 83.5 83.1 86.8 83.3 84.72 3.7 5 86.7 86.8 86 83.4 83.6 84.5 85.17 3.4 6 85.4 86.8 85.4 84.2 85.1 85.5 85.4 2.6 7 85.1 83.3 84.3 84.8 84.5 86 84.67 2.7 8 86.3 84.6 85 84.8 85.5 84.9 85.18 1.7 9 85.7 85.3 86.5 86.3 84.8 86.6 85.87 1.8 10 83.9 84.2. 85.8 86.9 83.7 84.9 84.9 3.2 AVERAGE 85.01 2.74 RANGE = LARGEST OBSERVATION - SMALLEST OBSERVATION XBAR = 85.01 RBAR = 2.74 A2 VALUE CORRESPONDING TO N = 6 = 0.483 CONTROL LIMITS FOR XBAR UCL X = XBAR + (A2 * RBAR) = 85.01 + (0.483 * 2.74) = 86.33 LCL X = XBAR - (A2 * RBAR) = 85.01 - (0.483 * 2.74) = 83.69 YES, SINCE ALL THE POINTS ARE WITHIN THE CONTROL LIMITS X-BAR UCL LCL MEAN X 87 85.87 8 6 85.4 85.17 85.18 84.85 84.9 85 84.75 -84:72 8467 84.57 84