Purpose: To determine the smallest unit of elementary charge. Method: An oil drop is balanced between...

  

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Purpose: To determine the smallest unit of elementary charge. Method: An oil drop is balanced between two large, horizontal parallel plates 1.00 cm apart. The mass of the oil drop was determined and recorded in the following table with the electric potential difference (voltage) between the plates. Use the data in the following table to answer the analysis questions. Mass of oil drop (x10-15) (kg) 4.95 6.10 7.53 4.44 3.49 3.92 5.50 6.61 3.84 4.02 3.65 4.11 5.02 5.30 4.25 4.46 4.98 5.60 4.53 4.81 Voltage between the plates (V) 506 535 763 537 305 305 840 807 774 491 746 835 340 811 517 546 510 488 688 585 Analysis: 1. Using a spreadsheet, determine the charge on each drop. 2. Examine your list of charges and find the smallest value. 3. Divide the smallest value into each of the other values you calculated. Use another calculated column. If all the values are close to a whole number proceed to step 6 4. If step 3 does not produce whole numbers then divide the smallest value found in step 2 by 2. Divide this new number into each of the other values for the charge from step 1 - Use another calculated column. If all the values are close to a whole number proceed to step 6 5. If step 4 does not produce whole numbers then divide the smallest value found in step 2 by 3. Divide this new number into each of the other values for the charge from step 1 - Use another calculated column. If all the values are close to a whole number proceed to step. This should do it. 6. Take the results of step 5 as whole numbers and divide the result into the charges calculated from step 1. Creating a new chart might be useful. 7. Find the rage of this calculation. It should be 1e in coulombs! You should have found the smallest possible charge using this method. Purpose: To determine the smallest unit of elementary charge. Method: An oil drop is balanced between two large, horizontal parallel plates 1.00 cm apart. The mass of the oil drop was determined and recorded in the following table with the electric potential difference (voltage) between the plates. Use the data in the following table to answer the analysis questions. Mass of oil drop (x10-15) (kg) 4.95 6.10 7.53 4.44 3.49 3.92 5.50 6.61 3.84 4.02 3.65 4.11 5.02 5.30 4.25 4.46 4.98 5.60 4.53 4.81 Voltage between the plates (V) 506 535 763 537 305 305 840 807 774 491 746 835 340 811 517 546 510 488 688 585 Analysis: 1. Using a spreadsheet, determine the charge on each drop. 2. Examine your list of charges and find the smallest value. 3. Divide the smallest value into each of the other values you calculated. Use another calculated column. If all the values are close to a whole number proceed to step 6 4. If step 3 does not produce whole numbers then divide the smallest value found in step 2 by 2. Divide this new number into each of the other values for the charge from step 1 - Use another calculated column. If all the values are close to a whole number proceed to step 6 5. If step 4 does not produce whole numbers then divide the smallest value found in step 2 by 3. Divide this new number into each of the other values for the charge from step 1 - Use another calculated column. If all the values are close to a whole number proceed to step. This should do it. 6. Take the results of step 5 as whole numbers and divide the result into the charges calculated from step 1. Creating a new chart might be useful. 7. Find the rage of this calculation. It should be 1e in coulombs! You should have found the smallest possible charge using this method.