QUESTION 2 A non-symmetrical rigid jointed portal frame ABCD is fixed at A and D. It...

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QUESTION 2 A non-symmetrical rigid jointed portal frame ABCD is fixed at A and D. It carries a trapezoidal distributed load acts along beam BC as illustrated in Figure Q2. The frame was constructed using a same steel section and material. The moment of inertia of the cross section is 1440 x 10 mm* and the Elastic Modulus of the material is 200 GPa. The sway analysis end moment is tabulated in Table Q2. a) Using the Moment Distribution Method, determine the final bending moments at both ends of each member. Note: Construct five loops of balance and answer should be rounded to two decimal points. b) Construct the shear force diagram for beam BC. Joint Member ΣΜ 15 kN/m 4.5 m A AB B 5m Figure Q2 Table Q2 B BA BC -73.58 -46.83 46.83 CB 21.75 с с 10 kN/m 7 m CD -21.75 D DC -21.23 (20 marks) QUESTION 2 A non-symmetrical rigid jointed portal frame ABCD is fixed at A and D. It carries a trapezoidal distributed load acts along beam BC as illustrated in Figure Q2. The frame was constructed using a same steel section and material. The moment of inertia of the cross section is 1440 x 10 mm* and the Elastic Modulus of the material is 200 GPa. The sway analysis end moment is tabulated in Table Q2. a) Using the Moment Distribution Method, determine the final bending moments at both ends of each member. Note: Construct five loops of balance and answer should be rounded to two decimal points. b) Construct the shear force diagram for beam BC. Joint Member ΣΜ 15 kN/m 4.5 m A AB B 5m Figure Q2 Table Q2 B BA BC -73.58 -46.83 46.83 CB 21.75 с с 10 kN/m 7 m CD -21.75 D DC -21.23 (20 marks)