Required identifying if the above 4 questions about limits are:

1) Real numbers, infinity or negative infinity.

2) They do not exist nor be calculated.

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Evaluate the following limits (as a real number, ∞o, or -co), or state that they do not exist. x²-16 lim X-4x²-5x+ This is a limit of the type, hence the expression has to be factorized: (x-4)(x+4) (x+4) This simplified version is continuous at 1, hence it may be (x-4)(x-1) (x-1) calculated by substitution: lim- √x+8 lim X-1 X² x²-1 x−4x2−5x+4 substitution: lim = √1+8 1² == (x+4) (4+4) 8 = lim X-4 (x-1) (4-1) 3 At x = 1 the denominator is not 0, hence the limit may be calculated by /x+8 X-1 X² = 3. = x²-16 x2-5x+4 00 | با = Evaluate the following limits (as a real number, ∞o, or -co), or state that they do not exist. x²-16 lim X-4x²-5x+ This is a limit of the type, hence the expression has to be factorized: (x-4)(x+4) (x+4) This simplified version is continuous at 1, hence it may be (x-4)(x-1) (x-1) calculated by substitution: lim- √x+8 lim X-1 X² x²-1 x−4x2−5x+4 substitution: lim = √1+8 1² == (x+4) (4+4) 8 = lim X-4 (x-1) (4-1) 3 At x = 1 the denominator is not 0, hence the limit may be calculated by /x+8 X-1 X² = 3. = x²-16 x2-5x+4 00 | با =

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Let us evaluate the given limits x16 72 l... View the full answer