Set up a numeric vector name x, consisting of 15 numbers, namely 10, 5, 3.1, 7.4,...
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Set up a numeric vector name x, consisting of 15 numbers, namely 10, 5, 3.1, 7.4, 11.7, 10.2, 5.8, 7.4, 11, 12, 12.5, 11.3, 10.6, 7, and 3. [1 point] Create a numeric vector y with 15 numbers, namely 12, 10, 5.6, 10.7, 5,10, 11, 6, 11.5, 12. 3, 12, 11, 10, 5.6 and 3 [1 point] Generates a new vector z of length 15 constructed by adding together, element by element, x repeated 2 times, y repeated just once, and the number 5 repeated 1 time. Show what z will be. Set up a numeric vector name x, consisting of 15 numbers, namely 10, 5, 3.1, 7.4, 11.7, 10.2, 5.8, 7.4, 11, 12, 12.5, 11.3, 10.6, 7, and 3. [1 point] Create a numeric vector y with 15 numbers, namely 12, 10, 5.6, 10.7, 5,10, 11, 6, 11.5, 12. 3, 12, 11, 10, 5.6 and 3 [1 point] Generates a new vector z of length 15 constructed by adding together, element by element, x repeated 2 times, y repeated just once, and the number 5 repeated 1 time. Show what z will be. Set up a numeric vector name x, consisting of 15 numbers, namely 10, 5, 3.1, 7.4, 11.7, 10.2, 5.8, 7.4, 11, 12, 12.5, 11.3, 10.6, 7, and 3. [1 point] Create a numeric vector y with 15 numbers, namely 12, 10, 5.6, 10.7, 5,10, 11, 6, 11.5, 12. 3, 12, 11, 10, 5.6 and 3 [1 point] Generates a new vector z of length 15 constructed by adding together, element by element, x repeated 2 times, y repeated just once, and the number 5 repeated 1 time. Show what z will be. Set up a numeric vector name x, consisting of 15 numbers, namely 10, 5, 3.1, 7.4, 11.7, 10.2, 5.8, 7.4, 11, 12, 12.5, 11.3, 10.6, 7, and 3. [1 point] Create a numeric vector y with 15 numbers, namely 12, 10, 5.6, 10.7, 5,10, 11, 6, 11.5, 12. 3, 12, 11, 10, 5.6 and 3 [1 point] Generates a new vector z of length 15 constructed by adding together, element by element, x repeated 2 times, y repeated just once, and the number 5 repeated 1 time. Show what z will be.
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Introduction to Java Programming, Comprehensive Version
ISBN: 978-0133761313
10th Edition
Authors: Y. Daniel Liang
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