NaHCO, (or Na CO) + HCl NaCl + HO + CO(g) 3. On the other...

  

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NaHCO, (or Na CO) + HCl → NaCl + H₂O + CO₂(g) 3. On the other hand, carbonate (CO) and bicarbonate (HCO) reacts with HCl(aq) according to the equation above. How does this reaction help you determine the weight of sodium bicarbonate in a mixture with sodium chloride? Consider this: When sodium bicarbonate and hydrochloric acid are mixed, the reaction between them generates three products. One of them, however, will not stay in the product mixture. Identify this product, and then, explain how the weight of the reactant mixture compared with the weight of the product mixture can be used to solve the problem. NaHCO, (or Na CO) + HCl → NaCl + H₂O + CO₂(g) 3. On the other hand, carbonate (CO) and bicarbonate (HCO) reacts with HCl(aq) according to the equation above. How does this reaction help you determine the weight of sodium bicarbonate in a mixture with sodium chloride? Consider this: When sodium bicarbonate and hydrochloric acid are mixed, the reaction between them generates three products. One of them, however, will not stay in the product mixture. Identify this product, and then, explain how the weight of the reactant mixture compared with the weight of the product mixture can be used to solve the problem.

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Solution The first reaction occurs when equimolar amounts of reactants are added together producin... View the full answer