Sodium bicarbonate (NaHCO3) is the conjugate base of carbonic acid (H2CO3. pKa = 6.37). First, draw the products of the reaction of sodium bicarbonate with phenol and acetic acid. Second, use your book to determine the pKa values of a phenol and a carboxylic acid. Third, determine which of these substances will react significantly (i.e.. Keq > I) with sodium bicarbonate. Explain your reasoning.

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lets break it down step by step 1 Products of the reaction of sodium bicarbonate with phenol and ace... View the full answer