Solution 9 Pw = 1000kg/m SG = fw = 0.5m 7/5x092 = 4.6. 8lokg/m Toookg/m 3 b = wookg/m v = 54104m/s 2= VP = lookg/mx5x10m/5x0.92 Solution: P+PAir + Parastihe h [1m =farm +/googens h 1300+12.054 +6664 1m =081 CS3008: FLUID MECHANICS h32m (2022) P=1.5kPa Air (C) F=100N Question 1: (a) If the density of a substance is 810 kg/m, what is its specific gravity and its specific weight? 4101-35kpas (b) A fluid with a specific gravity of 0.92 has a kinematic viscosity of 5x 104 m/s. What is the dynamic viscosity of the fluid? (c) A normal stress of 100 N is applied on a square solid surface with the length of 2 m. What is the pressure on the surface? OP= PH=PT = 1.551000x9- (d) (i) At what depth below the surface of a water body will the absolute pressure be equal to 200 kPa? (ii) If a 1.55-m-tall person orients himself vertically 15190 pa. underwater in a pool, what pressure difference does he feel between his head and his toes? Assume the density of water

Answer rating: 100% (QA)

Sure lets break this down step by step and address each question one at a time a The specific gravity of a substance is the ratio of the density of th... View the full answer