Someone has made a bet with a rival. The subject of the debate revolves around the...

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Someone has made a bet with a rival. The subject of the debate revolves around the properties of a certain liquid concoction and its actual characteris- tics/composition. The two major substances involved in the preparation of the concoction are (A) and (B). These two substances are initially combined in the gaseous phase in a tincture bottle. After a long amount of time, the tincture bottle contains both liquid and vapor. (A) and (B) are known to behave like ideal gases in the gas- phase, but the liquid possesses some interesting properties by comparison to separate pure liquids of (A) and (B). "Look, what I am saying is that liquid is not just (A) and (B). I think that in the liquid with (B), (A) actually combines to form (D), but no one has ever seen (D) in the vapor phase." You interpret this to mean that they believe (A) dimerizes in the liquid-state, which is representable as 2A(1) <--> > D(I) <--> > A₂ (1) and that (D) is essentially involatile. "Yeah, but that person thinks that (A) and (B) just have some special kind of interaction, which gives the liquid mixture its special properties. Can you help prove me right? You decide to investigate the matter. The following information may be relevant in the photo attached: 1. Determine the number of moles of vapor in equilibrium with the liquid concoction. 2. Under their hypothesis, your measurements have revealed there would be 0.005 total moles of liquid in the tincture. Determine the composition of the liquid concoction. (f you do not obtain an answer for this part and need one for subsequent parts, please use X₁ = 0.3, XB = 0.2, xp = 0.5. 3. Under their hypothesis, determine the Gibbs energy of reaction Agºrxn at 300 K. 4. Under the competing, other persons hypothesis, A does not form D. This would result in a different number of moles present in the liquid (not 0.005 because all D should instead be treated as A). Supposing that the total number of A particles remains equal to the total number present in either A or D from part b, find the new number of moles comprising the liquid. (If you do not obtain an answer for this part and require one for subsequent parts, please use 0.007 moles) 5. Determine whether there exist viable activity coefficients that would be consistent with the competing persons hypothesis. Someone has made a bet with a rival. The subject of the debate revolves around the properties of a certain liquid concoction and its actual characteris- tics/composition. The two major substances involved in the preparation of the concoction are (A) and (B). These two substances are initially combined in the gaseous phase in a tincture bottle. After a long amount of time, the tincture bottle contains both liquid and vapor. (A) and (B) are known to behave like ideal gases in the gas- phase, but the liquid possesses some interesting properties by comparison to separate pure liquids of (A) and (B). "Look, what I am saying is that liquid is not just (A) and (B). I think that in the liquid with (B), (A) actually combines to form (D), but no one has ever seen (D) in the vapor phase." You interpret this to mean that they believe (A) dimerizes in the liquid-state, which is representable as 2A(1) <--> > D(I) <--> > A₂ (1) and that (D) is essentially involatile. "Yeah, but that person thinks that (A) and (B) just have some special kind of interaction, which gives the liquid mixture its special properties. Can you help prove me right? You decide to investigate the matter. The following information may be relevant in the photo attached: 1. Determine the number of moles of vapor in equilibrium with the liquid concoction. 2. Under their hypothesis, your measurements have revealed there would be 0.005 total moles of liquid in the tincture. Determine the composition of the liquid concoction. (f you do not obtain an answer for this part and need one for subsequent parts, please use X₁ = 0.3, XB = 0.2, xp = 0.5. 3. Under their hypothesis, determine the Gibbs energy of reaction Agºrxn at 300 K. 4. Under the competing, other persons hypothesis, A does not form D. This would result in a different number of moles present in the liquid (not 0.005 because all D should instead be treated as A). Supposing that the total number of A particles remains equal to the total number present in either A or D from part b, find the new number of moles comprising the liquid. (If you do not obtain an answer for this part and require one for subsequent parts, please use 0.007 moles) 5. Determine whether there exist viable activity coefficients that would be consistent with the competing persons hypothesis.

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