Sometimes you have to do the problem in two steps: A car moving at 23 m/s...

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Sometimes you have to do the problem in two steps: A car moving at 23 m/s comes to a stop in 6 s. Find the distance it covers. == Here we see that vo = 23 m/s, v = 0 m/s (comes to a stop), and t = 6 s, and they want X. We don't have a formula that relates vo, v, t and x. So: first use v = vo + at to find a then use x = vot + 1/2 at to find x Your Answer: Answer Sometimes you have to do the problem in two steps: A car moving at 23 m/s comes to a stop in 6 s. Find the distance it covers. == Here we see that vo = 23 m/s, v = 0 m/s (comes to a stop), and t = 6 s, and they want X. We don't have a formula that relates vo, v, t and x. So: first use v = vo + at to find a then use x = vot + 1/2 at to find x Your Answer: Answer

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To find the distance covered by the car we can use the ... View the full answer