Steel ball with radius of 0.09 m lays on a bottom of the lake 5 m deep. What work is needed to lift the ball to the surface of the lake? Density of steel is 7860kg/m3. The volume of a sphere is fraction numerator 4 pi space r cubed over denominator 3 end fraction Use g = 9.8 m/s2 Calculate answer to two decimals.  

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Heres how to calculate the work needed to lift the steel ball to the surface of the lake 1 Find the volume of the steel ball Use the formula for the v... View the full answer