t Meth Bus (385:02) Exam #2 04/05/23 Question 3 of 9 Given the two-factor factorial experiment...

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t Meth Bus (385:02) Exam #2 04/05/23 Question 3 of 9 Given the two-factor factorial experiment and the ANOVA summary table to the right, fill in all the missing results. Source Degrees of Freedom (df) A B AB Error Total Fill in the missing results of the table. Source A B AB Error Total r-1=2 c-1=? (r-1)(c-1)=6 rc(n' -1)=24 n-1=? Sum of Squares SSA = ? SSB=15 SSAB = ? SSE = ? SST=? This test: 29 point(s) possible This question: 2 point(s) possible Submit test Mean Square (Variance) F MSA=35 MSB=? MSAB=15 FSTAT =? FSTAT =1 FSTAT =? MSE =? Degrees of Freedom r-1=2 c-1 = (r-1)(c-1)=6 rc(n' -1)=24 n-1= Sum of Squares SSA= SSB = 15 SSAB = SSE = SST= Mean Square (Variance) MSA=35 MSB= MSAB=15 MSE= F FSTAT FSTAT =1 FSTAT t Meth Bus (385:02) Exam #2 04/05/23 Question 3 of 9 Given the two-factor factorial experiment and the ANOVA summary table to the right, fill in all the missing results. Source Degrees of Freedom (df) A B AB Error Total Fill in the missing results of the table. Source A B AB Error Total r-1=2 c-1=? (r-1)(c-1)=6 rc(n' -1)=24 n-1=? Sum of Squares SSA = ? SSB=15 SSAB = ? SSE = ? SST=? This test: 29 point(s) possible This question: 2 point(s) possible Submit test Mean Square (Variance) F MSA=35 MSB=? MSAB=15 FSTAT =? FSTAT =1 FSTAT =? MSE =? Degrees of Freedom r-1=2 c-1 = (r-1)(c-1)=6 rc(n' -1)=24 n-1= Sum of Squares SSA= SSB = 15 SSAB = SSE = SST= Mean Square (Variance) MSA=35 MSB= MSAB=15 MSE= F FSTAT FSTAT =1 FSTAT