The acceleration of a particle is given by a=Asqrt(t) where A = 1.9m/s52. At t=0, v =
Fantastic news! We've Found the answer you've been seeking!
Question:
The acceleration of a particle is given by a=Asqrt(t) where A = 1.9m/s52. At t=0, v = 6.9m/s and x=0.
What is the speed as a function of time?
v=6.9m/s+(1.9m/s^5/2)sqrt(t)
v=6.9m/s+23(1.9m/s^5/2)t^3/2
v=6.9m/s+32(1.9m/s^5/2)t^3/2
v=6.9m/s+(1.9m/s^5/2)t^3/2
What is the displacement as a function of time?
x=(6.9m/s)t+3/5(1.9m/s^5/2)t^5/2 | |
x=(6.9m/s)t+4/15(1.9m/s5/2)t^5/2 | |
x=(6.9m/s)t+2/5(1.9m/s^5/2)t^5/2 | |
x=(6.9m/s)t+(1.9m/s^5/2)t^5/2 |
What is the acceleration at t = 5.0s ?
What is the speed at t = 5.0s ?
What is the displacement at t = 5.0s ?
Related Book For
Posted Date: