The algebra to find the actual distance is somewhat difficult, so it is useful to work...

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The algebra to find the actual distance is somewhat difficult, so it is useful to work the parts of this problem in a simpler context. Let's say that instead of finding the depth using a known time, we want to find the time for a given depth. So assume, only for this part, that the well is 29 m. For this and the next part, assume that the local acceleration due to gravity is 9.78 m/s and the current speed of sound in 337 m/s. (a) How long does it take the pebble to fall to the bottom of the well? T =(2D/g)^1/2 (b) How long does it take the noise to reach the top of the well? T = (c) How long does it take you to hear the splash after you drop the pebble? T = The algebra to find the actual distance is somewhat difficult, so it is useful to work the parts of this problem in a simpler context. Let's say that instead of finding the depth using a known time, we want to find the time for a given depth. So assume, only for this part, that the well is 29 m. For this and the next part, assume that the local acceleration due to gravity is 9.78 m/s and the current speed of sound in 337 m/s. (a) How long does it take the pebble to fall to the bottom of the well? T =(2D/g)^1/2 (b) How long does it take the noise to reach the top of the well? T = (c) How long does it take you to hear the splash after you drop the pebble? T =

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Lets work through each part of the problem a To find the time it takes for the pebble to fall to the ... View the full answer