The amount of lateral expansion (mils) was determined for a sample of n = 5 pulsed-power...

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The amount of lateral expansion (mils) was determined for a sample of n = 5 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.83 mils. Assuming normality, derive a 95% CI for o and for o. (Round your answers to two decimal places.) CI for o? mils? CI for o mils The amount of lateral expansion (mils) was determined for a sample of n = 5 pulsed-power gas metal arc welds used in LNG ship containment tanks. The resulting sample standard deviation was s = 2.83 mils. Assuming normality, derive a 95% CI for o and for o. (Round your answers to two decimal places.) CI for o? mils? CI for o mils