Prove the last law? The angles made with the plane of the interface are found from...

 

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Prove the last law? The angles made with the plane of the interface are found from E₁.az |E₁|cos(90°- 8₁) ⇒ = 5= √38 sin 0₁ 0₁ = 54.2° Ey.a, = |E2|\cos(90° – 02) » 2=V17sin0, s 0₂= 29.0° A useful relation can be obtained from pofolament 1)² + (Ey₁)² √(Ex¹)² + (Ey₁)² (D2² / €0 €₁²) tan 0₂ = Ezz √(Ex2)² + (Ey⁄2)² √(Ex2)² + (Ey2)² by division of these two equations gives tan ₁ Er = tan 0₂ Eri Prove the last law? The angles made with the plane of the interface are found from E₁.az |E₁|cos(90°- 8₁) ⇒ = 5= √38 sin 0₁ 0₁ = 54.2° Ey.a, = |E2|\cos(90° – 02) » 2=V17sin0, s 0₂= 29.0° A useful relation can be obtained from pofolament 1)² + (Ey₁)² √(Ex¹)² + (Ey₁)² (D2² / €0 €₁²) tan 0₂ = Ezz √(Ex2)² + (Ey⁄2)² √(Ex2)² + (Ey2)² by division of these two equations gives tan ₁ Er = tan 0₂ Eri

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To prove the relationship involving the angles of incidence and refraction at the interface between ... View the full answer