The balanced equation 2Cu(s) + O,(g) 2CUO(s) tells us that 1 mol of Cu =for...

 

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The balanced equation 2Cu(s) + O,(g) → 2CUO(s) tells us that 1 mol of Cu =for O must react with 32 g of O2 O produces 2 mol of Cuo O reacts with 1 mol of O, O cannot react with oxygen O produces 1 mol of Cuo D Question 2 10 pts A 3.0-mol sample of KCIO, was decomposed according to the equation 2KCIO(s) → 2KCI(s) + 302(g) How many moles of O2 are formed assuming 100% yield? O 4.0 mol O 4.5 mol O 2.0 mol O 25 mol O 3.0 mol The balanced equation 2Cu(s) + O,(g) → 2CUO(s) tells us that 1 mol of Cu =for O must react with 32 g of O2 O produces 2 mol of Cuo O reacts with 1 mol of O, O cannot react with oxygen O produces 1 mol of Cuo D Question 2 10 pts A 3.0-mol sample of KCIO, was decomposed according to the equation 2KCIO(s) → 2KCI(s) + 302(g) How many moles of O2 are formed assuming 100% yield? O 4.0 mol O 4.5 mol O 2.0 mol O 25 mol O 3.0 mol