The demand for a new computer game can be modeled by p(x)=59-5 In x, for 0x...

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The demand for a new computer game can be modeled by p(x)=59-5 In x, for 0≤x≤ 800, where p(x) is the price consumers will pay, in dollars, and x is the number of games sold, in thousands. Recall that total revenue is given by R(x)=x p(x). Complete parts (a) through (c) below. a) Find R(x). R(x) = b) Find the marginal revenue, R'(x). R'(x)= c) How many units will be sold if the price that consumers are willing to pay is $40? The number of units that will be sold is (Round to the nearest whole number as needed.) The demand for a new computer game can be modeled by p(x)=59-5 In x, for 0≤x≤ 800, where p(x) is the price consumers will pay, in dollars, and x is the number of games sold, in thousands. Recall that total revenue is given by R(x)=x p(x). Complete parts (a) through (c) below. a) Find R(x). R(x) = b) Find the marginal revenue, R'(x). R'(x)= c) How many units will be sold if the price that consumers are willing to pay is $40? The number of units that will be sold is (Round to the nearest whole number as needed.)