The figure below shows a 16-bit carry-bypass adder. The inputs are denoted as (A₁₅A₁₄…A₀) and (B₁₅B₁₄…B₀), where A₁₅ and B₁₅ are the MSBs. P_i and G_i follow the definitions in the lecture (i.e., P_i=A_i xor B_i, G_i=A_i & B_i). Outputs S_i are omitted for simplicity. Please note that independent calculations can be performed concurrently in hardware (e.g., all Pi’s and Gi’s can be calculated simultaneously).

The following figure shows the detail inside each full adder based on P and G.

 

Transcribed Image Text:

BP= P.P₂P:P, AB A₂,B₁ A₂,B₂ A₂, B₂ FA FA FA Co2 BP= P₂P₂P&P, A₂B₁ AB AB₁ A, B₁ FARFA FA FA Cos C06 Cot BP= P&P,P10P11 AB A,B, A1B10 ALB11 FARFARFARFA Co₂ Co.10 BP= P1:P13P14 P15 AB12 A1B13 A₁B₁4 A15B15 Coll FARFARFARFA► Coll Co,13 Coll 0,15 BP= P.P₂P:P, AB A₂,B₁ A₂,B₂ A₂, B₂ FA FA FA Co2 BP= P₂P₂P&P, A₂B₁ AB AB₁ A, B₁ FARFA FA FA Cos C06 Cot BP= P&P,P10P11 AB A,B, A1B10 ALB11 FARFARFARFA Co₂ Co.10 BP= P1:P13P14 P15 AB12 A1B13 A₁B₁4 A15B15 Coll FARFARFARFA► Coll Co,13 Coll 0,15

Answer rating: 100% (QA)

Inputs The adder takes two 16bit binary numbers A and B as inputs Each bit is labeled from A15 most significant bit to A0 least significant bit for A ... View the full answer