The figure below shows a meterstick (mass 0.150 kg and length L = 0.60 m) and...

 

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The figure below shows a meterstick (mass 0.150 kg and length L = 0.60 m) and a piece of clay (mass 0.075 kg) that is stuck to the left end of the meterstick. clay r ceiling L rope meter stick 1. Draw an extended free-body diagram of the meterstick in the situation shown above where it has just been released and is momentarily horizontal and suspended only by a rope tied a distance r = 0.4 m from the clay. Label the force arrows appropriately. Recall that the force of gravity on an object acts at the center of mass of that object. The center of mass of the meterstick is shown in the figure as an X, and treat the clay as a particle. You should end up with three forces acting on the meterstick. 2. Draw and label the distance vectors from the axis of rotation (where the rope is attached) to the point of application of those forces. 3. Calculate the net torque on the meterstick about the point where the rope is attached to the meterstick in the situation pictured above. 4. Calculate the center of mass of the meterstick + clay system relative to the left end of the meterstick. 5. Draw a new picture for the situation where the new suspension point (where the rope is attached to the meterstick) is at the center of mass of the meterstick + clay system you calculated in #4. 6. Draw an extended free-body diagram of the meterstick and the distance vectors for this new situation, and show that the net torque on the meterstick about the point where the rope is attached is now zero. The figure below shows a meterstick (mass 0.150 kg and length L = 0.60 m) and a piece of clay (mass 0.075 kg) that is stuck to the left end of the meterstick. clay r ceiling L rope meter stick 1. Draw an extended free-body diagram of the meterstick in the situation shown above where it has just been released and is momentarily horizontal and suspended only by a rope tied a distance r = 0.4 m from the clay. Label the force arrows appropriately. Recall that the force of gravity on an object acts at the center of mass of that object. The center of mass of the meterstick is shown in the figure as an X, and treat the clay as a particle. You should end up with three forces acting on the meterstick. 2. Draw and label the distance vectors from the axis of rotation (where the rope is attached) to the point of application of those forces. 3. Calculate the net torque on the meterstick about the point where the rope is attached to the meterstick in the situation pictured above. 4. Calculate the center of mass of the meterstick + clay system relative to the left end of the meterstick. 5. Draw a new picture for the situation where the new suspension point (where the rope is attached to the meterstick) is at the center of mass of the meterstick + clay system you calculated in #4. 6. Draw an extended free-body diagram of the meterstick and the distance vectors for this new situation, and show that the net torque on the meterstick about the point where the rope is attached is now zero.

Answer rating: 100% (QA)

In the given situation we will need to do the following for the first three steps 1 Draw an extended freebody diagram for the meterstick 2 Add the distance vectors for each force from the point of rot... View the full answer