Q1 The first term of a converging sequence {a} is given by, [4] a = 0...

 

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Q1 The first term of a converging sequence {a} is given by, [4] a₁ = 0 and the remaining terms can be generated using the following recursive relation, an+1 = √√3an + 10 Find the limit of the given sequence. Q2 Which of the following sequences {a}in (i) to (vi) Converge? If so, find the [18] limit of each converging sequence. (i) an = (n5-5n³+10)(n-5)² (n+-6n²+9) (3n+5)3 (ii) an = n n (1 - cos =) 25 (iii) (5+) (n+(-1)") (iv) n 5n-3n (v) 5n+3/ (vi) an = an = an = 72n4n 5-33-4nn! Q1 The first term of a converging sequence {a} is given by, [4] a₁ = 0 and the remaining terms can be generated using the following recursive relation, an+1 = √√3an + 10 Find the limit of the given sequence. Q2 Which of the following sequences {a}in (i) to (vi) Converge? If so, find the [18] limit of each converging sequence. (i) an = (n5-5n³+10)(n-5)² (n+-6n²+9) (3n+5)3 (ii) an = n n (1 - cos =) 25 (iii) (5+) (n+(-1)") (iv) n 5n-3n (v) 5n+3/ (vi) an = an = an = 72n4n 5-33-4nn!

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Given Q2 a 0 ant1 3anlo put n 1 a2 a 3a 10 9 10 Put n 2 3x to 10 az 441 all terms of the sequence is ... View the full answer