The identity (x^(2) + y^(2))^(2) = (x^(2) - y^(2))^(2) + (2xy)^(2) can be used to generate Pythagorean
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- The identity (x^(2) + y^(2))^(2) = (x^(2) - y^(2))^(2) + (2xy)^(2) can be used to generate Pythagorean triples. What Pythagorean triple could be generated using x = 8 and y = 3?
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