The nth harmonie of standing waves in a string of length L has a wavelength of $0\mathrm{.}4320$ m$,$ while the $($n$-1)$th harmonic has a wavelength of $0\mathrm{.}5400$ m$.$ Find L$,$ the length of the string.

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The nth harmonic of a standing wave on a string has a wavelength given by n 2Ln where L i... View the full answer