The over-the-air television channel 9 operates between frequencies 186 MHz and 192 MHz, with the video...

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The "over-the-air" television channel 9 operates between frequencies 186 MHz and 192 MHz, with the video and audio using different parts of this frequency range. To watch (and listen) to the channel properly, the tuner circuit in a television must resonate in the middle of this range (189 MHz) and produce a current over the whole range of at least 50% of the peak current at resonant frequency. A particular television tuning circuit is built with a 16.8 pF capacitor, a variable inductor, and a variable resistor. What value should the resistor be in order for the current at both 186 MHz and 192 MHz to be at least 50% of the current at the resonant frequency? Hint: You'll have to first calculate the value of the inductor so that the television tunes to channel 9. The "over-the-air" television channel 9 operates between frequencies 186 MHz and 192 MHz, with the video and audio using different parts of this frequency range. To watch (and listen) to the channel properly, the tuner circuit in a television must resonate in the middle of this range (189 MHz) and produce a current over the whole range of at least 50% of the peak current at resonant frequency. A particular television tuning circuit is built with a 16.8 pF capacitor, a variable inductor, and a variable resistor. What value should the resistor be in order for the current at both 186 MHz and 192 MHz to be at least 50% of the current at the resonant frequency? Hint: You'll have to first calculate the value of the inductor so that the television tunes to channel 9.

Answer rating: 100% (QA)

A fun problem Lets break it down step by step Step 1 Calculate the value of the inductor We need to ... View the full answer