The percentage shrinkage of two different types of casings selected randomly is givenbelow:Type 1: 0.20, 0.28, 0.12, 0.20, 0.24, 0.22, 0.32, 0.26, 0.32, 0.20Type 2: 0.10, 0.12, 0.15, 0.09, 0.20, 0.12, 0.14, 0.16, 0.18, 0.20Assume that the shrinkage follows normal distribution and has unequal variances.(i) Test the hypothesis that Type 1 casing produces more shrinkage than Type 2 casing.(ii) Find 90% confidence interval on the mean difference in shrinkage.

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Solution io The hypotheil ie For type 1 Sample Sze0 10 ND E ... View the full answer