The rate constant of a chemical reaction increased from 0.100 s1 to 3.10 s1 upon raising the

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Question:

The rate constant of a chemical reaction increased from 0.100 s−1 to 3.10 s−1 upon raising the temperature from 25.0 ∘C to 47.0 ∘C .

part A : Calculate the value of (1/T2−1/T1) where T1 is the initial temperature and T2 is the final temperature.

= K−1

Part B : Calculate the value of ln(k1/k2) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A.

Express your answer numerically.

Part C :

What is the activation energy of the reaction?

Express your answer numerically in kilojoules per mole.