The reaction of isopropanol, C3H8O with oxygen from air produces acetone in the presence of a catalyst

2C3H8O + O2 ---> 2C3H6O + 2H2O

The reactor is fed with a stream of 216 mol/h of C3H8O and the O2 is administered with a 35% excess from air. If the conversion of C3H8O is 83%. determine:

1.The stoichiometric oxygen consumed per hour considering the conversion percentage.
2.The molar ratio of air to isopropanol in the reaction.
3.The composition of the output stream, in molar percentage. in one hour of operation.

Answer rating: 100% (QA)

To solve the problem well first calculate the stoichiometric amounts of oxygen and other components involved in the reaction and then use that information to determine the molar ratio and composition ... View the full answer