The setup used in our laboratory produces entangled photons through the process of spon- taneous parametric...
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The setup used in our laboratory produces entangled photons through the process of spon- taneous parametric down conversion. It uses a birefringent crystal to convert UV photons (400 nm) into two IR photons (800 nm) which are entangled in their polarisation. The ideal entangled state that we want to study is the antisymmetric singlet (see lecture notes) 1 |DEPR) = (VAHB) - HAVB)) where the A,B are the two detectors, and {V), H)} represents the vertical and horizontal polarisation basis. We use the notation VAHB) = |VA|H)B to denote the state with a vertical polarised photon detected at A and a horizontal polarised photon detected at B. In the experiment, there are three more EPR states that can be prepared and selected using half-wave plates. Let's denote these EPR states as 1 |DEPR) = (VAHB) + |HAVB)) 1 VEPR)=√(HAHB) + VAVB)) VEPR) (HAHB) - VAVB)) Suppose that you can control the experiment such that each member of your group gets one unique state from above. For each of these new EPR states, calculate the quantum mechanical correlation E(a, 3) for two arbitrary angles of the polarisers at the detector A and B, and then find a set of four angles {a, 3, d', 3'} that violate the CHSH inequality E(a, 3) - E(a, 3') + E(a', 3) + E(a', B')| ≤ 2 Do you all obtain the same angles that violate the CHSH inequality? If yes, why? If not, why? = The setup used in our laboratory produces entangled photons through the process of spon- taneous parametric down conversion. It uses a birefringent crystal to convert UV photons (400 nm) into two IR photons (800 nm) which are entangled in their polarisation. The ideal entangled state that we want to study is the antisymmetric singlet (see lecture notes) 1 |DEPR) = (VAHB) - HAVB)) where the A,B are the two detectors, and {V), H)} represents the vertical and horizontal polarisation basis. We use the notation VAHB) = |VA|H)B to denote the state with a vertical polarised photon detected at A and a horizontal polarised photon detected at B. In the experiment, there are three more EPR states that can be prepared and selected using half-wave plates. Let's denote these EPR states as 1 |DEPR) = (VAHB) + |HAVB)) 1 VEPR)=√(HAHB) + VAVB)) VEPR) (HAHB) - VAVB)) Suppose that you can control the experiment such that each member of your group gets one unique state from above. For each of these new EPR states, calculate the quantum mechanical correlation E(a, 3) for two arbitrary angles of the polarisers at the detector A and B, and then find a set of four angles {a, 3, d', 3'} that violate the CHSH inequality E(a, 3) - E(a, 3') + E(a', 3) + E(a', B')| ≤ 2 Do you all obtain the same angles that violate the CHSH inequality? If yes, why? If not, why? =
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ANS WER Yes we all obtain the same angles that violate the CH SH inequality This is because t... View the full answer
Related Book For
Physics for Scientists and Engineers A Strategic Approach with Modern Physics
ISBN: 978-0133942651
4th edition
Authors: Randall D. Knight
Posted Date:
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