The solution of a certain differential equation is of the form y(t) = a exp(3t) +...

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The solution of a certain differential equation is of the form y(t) = a exp(3t) + bexp(4t), where a and b are constants. The solution has initial conditions y(0) = 1 and y' (0) = 4. Find the solution by using the initial conditions to get linear equations for a and b. y(t) = The solution of a certain differential equation is of the form y(t) = a exp(3t) + bexp(4t), where a and b are constants. The solution has initial conditions y(0) = 1 and y' (0) = 4. Find the solution by using the initial conditions to get linear equations for a and b. y(t) =