The total electric field at a point on the axis of a uniformly charged disk, which...

Transcribed Image Text:

The total electric field at a point on the axis of a uniformly charged disk, which has a radius R and a uniform charge density of , is given by the following expression, where x is the distance of the point from the disk. Ex=2ke[] X (R + x2)1/2 Consider a disk of radius R = 2.70 cm having a uniformly distributed charge of +5.73 . (a) Using the expression above, compute the electric field at a point on the axis and 2.82 mm from the center. N/C (b) Explain how the answer to part (a) compares with the field computed from the near-field approximation E = 0/280 This answer has not been graded yet. (c) Using the first expression above, compute the electric field at a point on the axis and 28.2 cm from the center of the disk. N/C (d) Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +5.73-C charged particle at a distance of 28.2 cm. This answer has not been graded yet. The total electric field at a point on the axis of a uniformly charged disk, which has a radius R and a uniform charge density of , is given by the following expression, where x is the distance of the point from the disk. Ex=2ke[] X (R + x2)1/2 Consider a disk of radius R = 2.70 cm having a uniformly distributed charge of +5.73 . (a) Using the expression above, compute the electric field at a point on the axis and 2.82 mm from the center. N/C (b) Explain how the answer to part (a) compares with the field computed from the near-field approximation E = 0/280 This answer has not been graded yet. (c) Using the first expression above, compute the electric field at a point on the axis and 28.2 cm from the center of the disk. N/C (d) Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +5.73-C charged particle at a distance of 28.2 cm. This answer has not been graded yet.

Answer rating: 100% (QA)

a To compute the electric field at a point on the axis and 282 mm from the center of the disk we can ... View the full answer